If the line 3x - 2y + 6 = 0 meets X-axis and Y-axis, respectively at A and B, then the equation of the circle with radius AB and centre at A is
x2 + y2 + 4x + 9 = 0
x2 + y2 + 4x - 9 = 0
x2 + y2 + 4x + 4 = 0
x2 + y2 + 4x - 4 = 0
A line l meets the circle x2 + y2 = 61 in A, B and P(- 5, 6) is such that PA = PB = 10. Then,the equation of l is
5x + 6y + 11 = 0
5x - 6y - 11 = 0
5x - 6y + 11 = 0
5x - 6y + 11 = 0
C.
5x - 6y + 11 = 0
Since, the line l meets the circle x2 + y2 = 61 at two points A and B.
Thus, PM is perpendicular to AB and OM is perpendicular to the chord AB, therefore OP is perpendicular to AB.
If (1, a), (b, 2) are conjugate points with respect to the circle x2 + y2 = 25, then 4a + 2b is equal to
25
50
100
150
If x - y + 1 = 0 meets the circlex2 + y2 + y - 1 = 0 at A and B, then the equation of the circle with AB as diameter is
2(x2 + y2) + 3x - y + 1 = 0
2 (x2 + y2) + 3x - y + 2 = 0
2(x2 + y2) + 3x - y + 3 = 0
x2 + y2 + 3x - y + 1 = 0
If y = 3x is a tangent to a circle with centre (1, 1), then the other tangent drawn through (0, 0) to the circle is
3y = x
y = - 3x
y = 2x
y = - 2x
Let O be the origin and A be a point on the curve y = 4x. Then the locus of the mid point of OA is :
x2 = 4y
x2 = 2y
y2 = 16x
y2 = 2x