For the parabola y2 + 6y - 2x + 5 = 0(I) The vertex is (- 2, - 3)(II) The directrix is y + 3 = 0Which of the following is correct ? | Conic Section

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 Multiple Choice QuestionsMultiple Choice Questions

281.

The number of common tangents to the two circles x2 + y - 8x + 2y = 0 and x2 + y2 - 2x - 16y + 25 = 0 is :

  • 1

  • 2

  • 3

  • 4


282.

Observe the following statements :

I. The circle x2 + y2 - 6x - 4y - 7 = 0 touches y-axis.

II. The circle x2 + y2 + 6x + 4y - 7 = 0 touches

x-axis. Which of the following is a correct statement ?

  • Both I and II are true

  • Neither I nor II is true

  • I is true, II is false

  • I is false, II is true


283.

The length of the tangent drawn to the circle x2 + y2 - 2x + 4y - 11 = 0

  • 1

  • 2

  • 3

  • 4


284.

Equations of the latus rectum of the ellipse

9x2 + 4y2 - 18x - 8y - 23 = 0 are : 

  • y = ± 5

  • x = ± 5

  • y = 1 ± 5

  • x = - 1 ± 5


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285.

The equation of the circle of radius 3 that lies in the fourth quadrant and touching the lines x = 0 and y = 0 is

  • x2 + y2 - 6x + 6y + 9 = 0

  • x2 + y2 - 6x - 6y + 9 = 0

  • x2 + y2 + 6x - 6y + 9 = 0

  • x2 + y2 + 6x + 6y + 9 = 0


286.

The inverse point of (1, 2) with respect to the circle

x2 + y2 - 4x - 6y + 9 = 0 is

  • (0, 0)

  • (1, 0)

  • (0, 1)

  • (1, 1)


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287.

For the parabola y2 + 6y - 2x + 5 = 0

(I) The vertex is (- 2, - 3)

(II) The directrix is y + 3 = 0

Which of the following is correct ?

  • Both I and II are true

  • I is true, II is false

  • I is false, II is true

  • Both I and II are false


B.

I is true, II is false

Given parabola is y2 + 6y - 2x + 5 = 0            y2 + 6y + 9 - 9 - 2x + 5 = 0  y + 32 = 2x + 4  y + 32 = 2x + 2Vertex of parabola is  - 2, - 3 = h, kEquation of diretrix is x - h + a = 0 x +2 +12 = 0        2x + 5 = 0 I is true and II is false.


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288.

The value of k, If (1, 2), (k, - 1) are conjugate points with respect to the ellipse 2x2 + 3y2 = 6 is

  • 2

  • 4

  • 6

  • 8


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289.

If the line lx + my = 1 is a normal to the hyperbola

x2a2 - y2b2 = 1, then a2l2 - b2m2 is equal to

  • a2 - b2

  • a2 + b2

  • (a2 + b2)2

  • (a2 - b2)2


290.

If the lines 2x - 3y = 5 and 3x - 4y = 7 are two diameters of a circle of radius 7, then the equation of the circle is

  • x2 + y2 + 2x - 4y - 47 = 0

  • x2 + y2 = 49

  • x2 + y2 - 2x + 2y - 47 = 0

  • x2 + y2 = 17


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