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 Multiple Choice QuestionsMultiple Choice Questions

31.

(+)-2-chloro-2-phenylethane in toluene racemises slowly in the presence of small amount of SbCl2, due to the formation of

  • carbanion

  • carbene

  • free-radical

  • carbocation


32.

Correct pair of compounds which gives blue colouration/precipitate and white precipitate, respectively, when their Lassaigne's test is separately done is

  • NH2NH2, HCl and ClCH2COOH

  • NH2CSNH2 and PhCH2Cl

  • NH2NH2, COOH and NH2CONH2


33.

2-methylpropane on monochlorination under photochemical condition give

  • 2-chloro-2-methylpropane as major product

  • (1 : 1) mixture of 1-chloro-2-methylpropane and 2-chloro-2-methyl propane

  • 1-chloro-2-methyl propane as a major product

  • (1 : 9) mixture of 1-chloro-2-methylpropane and 2-chloro-2-methylpropane


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34.

The most likely protonation site in the following molecule is    

                        

 

  • C-1

  • C-2

  • C-3

  • C-6


A.

C-1

Addition of a proton at C1 results in the formation of tropylium carbocation (an aromatic species with more stability due to delocalisation of π electrons), thus, it is the most reactive site towards protonation. Addition of proton at any other carbon atom, interupt in the delocaiisation of π electrons by disturbing planarity of molecules and hence, makes it less stable. Thus, these all are less reactive towards protonation.

                   


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35.

The optically active molecule is


36.

An optically active compound having molecular formula C2H16 on ozonolysis gives acetone as one of the products. The structure of the compound is


37.

Among the following statements about the molecules X and Y, the one(s) which correct is (are)

                

  

  • X and Y are diastereomers

  • X and Y are enantiomers

  • X and Y are both aldohexoses

  • Xis a D-sugar and Y is an L-sugar


38.

The correct structure of the dipeptide gly-ala is


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39.

Amongst the following, the one which can exist in free state as stable compound is

  • C7H9O

  • C8H12O

  • C6H12O

  • C10H17O


 Multiple Choice QuestionsShort Answer Type

40.

Compound A treated with NaNH2 followed by CH3CH2Br gave compound B. Partial hydrogenation of compound B produced compound C, which on ozonolysis gave a  carbonyl compound D, (C3H6O). Compound D did not respond to iodoform test with I2/KI and NaOH. Find out the structures of A, B, C and D.


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