Suppose f(x) = x(x + 3)(x - 2), x [- 1, 4]. Then, a value of c in (- 1, 4) satisfying f'(c) = 10 is
2
3
C.
For the function f(x) = (x - 1)(x - 2) defined on [0, ½] the value of c satisfying Lagrange's mean value theorem is
Let f(x) be a quadratic polynomial such that f( – 1) + f(2) = 0. If one of the roots of f(x) = 0 is 3, then its other root lies in :
(1, 3)
( - 1, 0)
( - 3, - 1)
(0, 1)