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 Multiple Choice QuestionsMultiple Choice Questions

121.

If cosx + cos2x = 1, then the value of sin12x + 3sin10x + 3sin8x + sin6x - 1, is equal to :

  • 2

  • 1

  • - 1

  • 0


122.

The product of all values of cosα + isinα3/5 is :

  • 1

  • cosα + isinα

  • cos3α + isin3α

  • cos5α + isin5α


123.

1 + cosπ81 + cos3π81 + cos5π81 + cos7π8 is equal to

  • 12

  • 18

  • cosπ8

  • 14


124.

If 3cosθ + sinθ = 2, then the value of θ is

  •  + - 1nπ4

  • - 1nπ4 - π3

  •  + π4 - π3

  •  + - 1nπ4 - π3


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125.

If in a AABC, (s - a)(s - b) = s(s - c) then angle C is equal to

  • 90°

  • 45°

  • 30°

  • 60°


126.

The length of the shadows of a vertical pole of height h, thrown by the sun's rays at three different moments are h, 2h and 3h. The sum of the angles of elevation of the rays at these three moments is equal to

  • π2

  • π3

  • π4

  • π6


127.

cos4π8 + cos43π8 +cos45π8 + cos47π8 is equal to

  • 32

  • - 23

  • - 1

  • 1


128.

Number of solutions of the equationan tanx + secx = 2cosx lying in the interval 0, 2π is

  • 0

  • 1

  • 2

  • 3


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129.

In a triangle ABC, if tanA2 = 56 and tanB2 = 2037 , then a + c is equal to

  • b

  • 2b

  • 3b

  • 4b


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130.

In a ABC, if tanA2 = 56 and tanC2 = 25, then the sides a, b, c are in

  • AP

  • GP

  • HP

  • None of these


A.

AP

Given, tanA2 = 56 and tanC2 = 25 tanA2 + C2 = 56 + 251 - 56 × 25 = 3720 cotB2 = 3720  tanB2 = 3720 sinA = 2tanA21 + tan2A2 = 2 × 561 + 2536 = 6061sinB = 2tanB21 + tan2B2 = 2 × 20371 + 4001369 = 14801769sinC = 2tanC21 + tan2C2 = 2 × 251 + 425 = 2029Using sine rule,asinA = bsinB = csinC a6061 = b14801769 = c2029 = k a = 6061k, b = 14801769k, c = 2029kNow, a +c = 6061k + 2029k = 2960k1769    a + c = 2bHence, a, b and c are in AP.


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