If three positive real numbers a, b, c are in AP and abc = 4, then the minimum possible value of b is 2
If i = and n is a positive integer, then in + in + 1 + in + 3 is equal to
1
i
in
0
D.
0
in(1 + i + i2 + i3) = in(1 + i - 1 - i)
= 0
If a, b, c are in GP (a> 1, b > 1, c > 1), then for any real number x (with x > 0, x 1), are in
GP
AP
HP
GP but not in HP