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 Multiple Choice QuestionsMultiple Choice Questions

291.

Catalytic dehydrogenation of a primary alcohol gives a

  • secondary alcohol

  • aldehyde

  • ketone

  • ester


292.

The product formed when hydroxylamine condenses with a carbonyl compound is called

  • hydrazide

  • oxime

  • hydrazine

  • hydrazone


293.

The compound on dehydrogenation gives a ketone. The original compound is

  • primary alcohol 

  • secondary alcohol

  • tertiary alcohol

  • carboxylic acid


294.

Which of the following organic compounds answers to both iodoform test and Fehling's test?

  • Ethanol

  • Methanal

  • Ethanal

  • Propanone


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295.

CH3COOH LiAlH4 X 300°CCu Y NaOHDilute Z

In the above reaction Z is

  • Butanol

  • Aldol

  • Ketol

  • Acetal


296.

The compound which forms acetaldehyde when heated with dilute NaOH, is

  • 1, 1-dichloroethane

  • 1, 1, 1-trichloroethane

  • 1-chloroethane

  • 1, 2-dichloroethane


297.

The compound obtained when acetaldehyde reacts with dilute aqueous sodium hydroxide exhibits

  • geometrical isomerism

  • optical isomerism

  • neither optical nor geometrical isomerism

  • both optical and geometrical isomerism


298.

Benzaldehyde and acetone can be best distinguished using

  • Fehling's solution

  • Sodium hydroxide solution

  • 2, 4-DNP

  • Tollen's reagent


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299.

One mole of an organic compound A with the formula C3H8O reacts completely With two moles of HI to form X and Y. When Y is boiled with aqueous alkali it forms Z. Z answers the iodoform test. The compound A is

  • propan-2-ol

  • propan-1-ol

  • ethoxyethane

  • methoxyethane


D.

methoxyethane

Molecular formula C3H8O (CnH2n+2O) suggests that the organic compound is either alcohol or ether.
Since, the compound on reaction with HI gives two different compounds, it must be an unsymmetrical ether, and its formula must be CH3OC2H5 (methoxyethane).

The reaction are as follows

CH3OC2H5methoxyethane + 2HI  CH3I X+ C2H5OHYC2H5OH + NaOHaqueous + I2  CHI3Iodoform + HCOONa + H2O + NaI


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300.

The correct sequence ofsteps involved in the mechanism of Cannizaro's reaction is

  • nucleophilic attack, transfer of H- and transfer of H+

  • transfer of H-, transfer of H+ and nucleophilic attack

  • transfer if H+, nucleophilic attack and transfer of H-

  • electrophilic attack by OH-, transfer of H+ and transfer of H-


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