Fluorine exhibits an oxidation state of only -1 because:
it can readily accept an electron
it is very strongly electronegative
it is a non-metal
it belong to halogen family
Which among the following factors is the most important in making fluorine the strongest oxidizing agent ?
Electron affinity
Ionization enthalpy
Hydration enthalpy
Bond dissociation energy
C.
Hydration enthalpy
F2 has the most negative value which is dependent on hydration enthalpy.
The oxidation states of iodine in HIO4 H3IO5 and H5IO6, are respectively :
+ 1, + 3, + 7
+ 7, + 7, + 3
+ 7, + 7, + 7
7, + 5, + 3
Amphoteric-oxide combinations are in:
ZnO, K2O, SO3
ZnO, P2O5, Cl2O7
SnO2, Al2O3, ZnO
PbO2, SnO2, SO3