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 Multiple Choice QuestionsMultiple Choice Questions

101.

If cotcos-1x = sectan-1ab2 - a2, then x is equal to

  • b2b2 - a2

  • a2b2 - a2

  • 2b2 - a2a

  • 2b2 - a2b


102.

Number of solutions ofthe equation

tan-112x + 1 + tan-114x + 1 = tan-12x2 is

  • 1

  • 2

  • 3

  • 4


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103.

The value of tan-112 + tan-113 + tan-178 is

  • tan-178

  • cot-115

  • tan-115

  • tan-12524


C.

tan-115

tan-112 + tan-113 + tan-178= tan-112 + 131 - 12 . 13 + tan-178           tan-1a + tan-1b = tan-1a +b1 - ab= tan-15656 + tan-178= tan-11 + tan-178= tan-11 + 781 - 78 = tan-115


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104.

If tan-1x - 1 + tan-1x + tan-1x + 1 = tan-13x, then x is

  • ± 12

  • 0, 12

  • 0, - 12

  • 0, ± 12


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105.

The domain of the function sin-1log2x22 is

  • [- 1, 2] - {0}

  • [- 2, 2] - (- 1, 1)

  • [- 2, 2] - {0}

  • [1, 2]


106.

3tan-1a is equal to

  • tan-13a + a31 + 3a2

  • tan-13a - a31 + 3a2

  • tan-13a + a31 - 3a2

  • tan-13a - a31 - 3a2


107.

The value of sinsin-113 + sec-13 + costan-112 + tan-12 is :

  • 1

  • 2

  • 3

  • 4


108.

The value of cot-19 + csc-1414 is given by :

  • 0

  • π4

  • π2

  • tan-12


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109.

cos-112 + 2sin-112 is equal to :

  • π4

  • π6

  • π3

  • 2π3


110.

A particle possess two velocities simultaneously at an angle of tan-1125; to each other. Their resultant is 15 m/s. If one velocity is 13 m/s, then the other will be :

  • 5 m/s

  • 4 m/s

  • 12 m/s

  • 13 m/s


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