Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

191.

If f : R  R is defined by f(x) = lxl, then

  • f-1(x) = - x

  • f-11x

  • the function f-1(x) does not exist

  • f-1x = 1x


192.

On the set of all natural numbers N, which one of the following * is a binary operation?

  • a * b = ab

  • a * b = a - ba + b

  • a * b = a + 3b

  • a * b = 3a - 4b


193.

On the set of integers Z, define f : Z  Z as f(n) = n2, n is even0,  n is odd, then 'f' is

  • injective but not surjective

  • neither injective nor surjective

  • surjective but not injective

  • bijective


194.

The inverse of 2010 in the group Q* of all positive rational under the binary operation * defined by a * b = ab2010, a, b  Q+ is

  • 2009

  • 2011

  • 1

  • 2010


Advertisement
195.

Define a relation R on A = {1, 2, 3, 4} as xRy if x divides y. R is

  • reflexive and transitive

  • reflexive and symmetric

  • symmetric and transitive

  • equivalence


196.

On the set of all non-zero reals, an operation * is defined as a * b = 3ab2. In this group, a solution of (2 * x) * 3-1 = 4-1 is

  • 6

  • 1

  • 1/6

  • 3/2


197.

If A and B have n elements in common, then the numberofelements common to A x B and B x A is

  • n

  • 2n

  • n2

  • 0


198.

Which of the following is false ?

  • (N, *) is a group

  • (N, +) is a semi-group

  • (Z, +) is a group

  • Set of even integers is a group under usual addition


Advertisement
Advertisement

199.

Let S be the set of all real numbers. A relation R has been defined on S by aRb  a - b  1, then R is

  • symmetric and transitive but not reflexive

  • reflexive and transitive but not symmetrIc

  • reflexive and symmetric but not transitive

  • an equivalence relation


C.

reflexive and symmetric but not transitive

Given, aRb  a - b  1For ReflexiveaRa = a - a =  1So, it is reflexive.For SymmetricaRb  a - b  1         b - a  1i.e.,             aRb  bRaSo, it is symmetric.ForTransitiveTake a = 1, b = 2 and c = 3Now, a - b = 1 - 2 = 1and    b - c = 2 - 3 = 1But     a - c = 1 - 3 = 2 > 1, which is not true.So, it is not transitive.


Advertisement
200.

For any two real numbers, an operation * defined by a * b  = 1 + ab is

  • neither commutative nor associative

  • commutative but not associative

  • both commutative and associative

  • associative but not commutative


Advertisement