Which carbocation is most stable ?
CH3CH
C
C6H5C
CH3CH2C
C.
C6H5C
A phenyl group, in which there is a flow of electron due to resonance of the benzene ring, generally causes -I effect, but can act as both electron donating as well as electron withdrawing groups, depending upon the nature of group with which it is attached. In C6H5CH phenyl group is attached to electron deficient group, hence it will donate electron due to resonance in benzene ring and thus stabilise the cation.
Which of the following is the correct increasing order of stability of free radicals.
(CH3)2CH0 < (CH3)2CH0 < (C6H5)20CH < (C6H5)3C0
(CH3)2CH0 < (CH3)2C0 < (C6H5)30C < (C6H5)2C0
(C6H5)30C < (C6H5)20CH < (CH3)30C < (CH3)20CH
(C6H5)20CH < (C6H5)2C0 < (CH3)30C < (CH3)20CH
The number of enantiomers and mesa forms for the compound ,
HOOC-CH(CH3)-CHOH-CHBr-CHOHCH(CH3)-COOH are respectively:
12 , 2
12 , 4
8 , 4
8 , 2
Which of the following yields as a major product is mono chlorination of ethyl benzene in the presence of light and heat.
m- chlorotoluene
a mixture of -O- and p-chlorotoluene
1-chloro-2- phenylethane
1-chloro -1- phenyl ethane
The correct IUPAC name of
4-methyoxy -2- nitrobenzaldehyde
4-formyl -3- nitro anisole
4- methoxy -6- nitrobenzaldehyde
2-formyl -5- methoxy nitrobenzene
The correct order of stability of carbocations, is :
1 < 2 < 3 < CH3
H3 < 1 < 2 < 3
3 < 2 < 1 < H3
2 < 3 < 1 < H3
The IUPAC name of the following compound is
bicyclo [2, 2, 0] octane
bicyclo [0, 2, 2] hexane
bicyclo [2, 1, 1] hexane
bicyclo [2, 2, 0] hexane
The following compound can not exhibit
CH3CH = CH - CH(OH).COOH
geometrical isomerism
optical isomerism
metamerism
position isomerism