CBSE
Multiple Choice Questions1 newton/coulomb is equivalent to
1 C/V
1 J
1 V/M
1 J/C
What is the angle between the electric dipole moment and the electric field strength due to it on the equatorial line?
0°
90°
180°
None of these
Two spheres of radii R1 and R2 respectively are charged and joined by a wire. The ratio of the electric field of spheres is :
Two charges each of equal magnitude 3.2 x 10-19 coulomb but of opposite sign form an electric dipole. The distance between the two charges is 2.4 . If the dipole is placed in an electric field of 5 x 105 volt/metre, then in equilibrium its potential energy will be
3 × 15-23 joule
-3.84 × 10-23 joule
-6 × 10-23 joule
-2 × 10-26 joule
An electron is moving with velocity v on a circular path of radius r in a transverse electric field B. The specific charge (e/m) of the electron is
Bvr
Bvr2
Two small charged spheres A and B have charges 10 C and 40 C respectively and are held at a separation of 90 cm from each other. At what distance from A, the electric intensity would be zero?
22.5 cm
18 cm
36 cm
30 cm
A charged particle moves in an electric field from A to B, then from B to A :
If WAB > WBA, then the field is conservative
If WAB + WBA = 0, then the field is conservative
If WAB + WBA > 0, then the field is conservative
If WAB = WBA, then the field is conservative
The unit of permittivity () of space is
newton-metre2 / coulomb2
coulomb / newton-metre
coulomb / newton-metre2
coulomb2 / newton-metre2
The figure shows three points A, B and C in a region of a uniform electric field . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good?
VA = VB = VC
VA = VB > VC
VA = VB < VC
VA > VB = VC
Number of extra electrons in a body of charge -80C, is
80 × 1015
80 × 10−15
5 × 1014
1.28 × 10−17
