CBSE
Multiple Choice QuestionsNumber of extra electrons in a body of charge -80C, is
80 × 1015
80 × 10−15
5 × 1014
1.28 × 10−17
What is the angle between the electric dipole moment and the electric field strength due to it on the equatorial line?
0°
90°
180°
None of these
1 newton/coulomb is equivalent to
1 C/V
1 J
1 V/M
1 J/C
Two small charged spheres A and B have charges 10 C and 40 C respectively and are held at a separation of 90 cm from each other. At what distance from A, the electric intensity would be zero?
22.5 cm
18 cm
36 cm
30 cm
An electron is moving with velocity v on a circular path of radius r in a transverse electric field B. The specific charge (e/m) of the electron is
Bvr
Bvr2
The unit of permittivity () of space is
newton-metre2 / coulomb2
coulomb / newton-metre
coulomb / newton-metre2
coulomb2 / newton-metre2
A charged particle moves in an electric field from A to B, then from B to A :
If WAB > WBA, then the field is conservative
If WAB + WBA = 0, then the field is conservative
If WAB + WBA > 0, then the field is conservative
If WAB = WBA, then the field is conservative
Two charges each of equal magnitude 3.2 x 10-19 coulomb but of opposite sign form an electric dipole. The distance between the two charges is 2.4 . If the dipole is placed in an electric field of 5 x 105 volt/metre, then in equilibrium its potential energy will be
3 × 15-23 joule
-3.84 × 10-23 joule
-6 × 10-23 joule
-2 × 10-26 joule
Two spheres of radii R1 and R2 respectively are charged and joined by a wire. The ratio of the electric field of spheres is :
The figure shows three points A, B and C in a region of a uniform electric field . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good?
VA = VB = VC
VA = VB > VC
VA = VB < VC
VA > VB = VC
