A capacitor of capacity C is charged by connecting it from Class Physics Electrostatic Potential and Capacitance

Book Store

Download books and chapters from book store.
Currently only available for.
CBSE

Subject

Physics
zigya logo

NEET Physics : Electrostatic Potential and Capacitance

Multiple Choice Questions

121.

Two capacitors, one 4 pF and the other 6 pF, connected in parallel, are charged by a 100 V battery. The energy stored in the capacitors is

  • 1.2 × 10−8 J

  • 2.4 × 10−8 J

  • 5.0 × 10−8 J

  • 1.2 × 10−6



122.

What is the area of the plate of a 3 F parallel plate capacitor, if the separation between the plates is 5 mm?

  • 12.981 x 102 m2

  • 9.281 × 109 m2

  • 1.69 × 1012 m2

  • 4.529 × 109 m2



123.

Equivalent capacity between A and B is

  • 2 µF

  • 3 µF

  • 4 µF

  • 0.5 µF



124.

A sheet of aluminium foil of negligible thickness is introduced between the plates of a capacitor. The capacitance of the capacitor

  • decreases

  • remains unchanged

  • becomes infinite

  • increases



125.

The diameter of each plate of an air capacitor is 4 cm. To make the capacity of this plate capacitor equal to that of 20 cm diameter sphere, the distance between the plates will be

  • 4 × 10-3 m

  • 1 × 10-3 m

  • 1 cm

  • 1 × 10-3 cm



126.

A capacitor of capacity C is charged by connecting it with R according to the figure. Energy supplied by the battery in this process is :

 

  • more than  12CV2

  • 12CV2

  • 2CV2

  • less than 12CV2



127.

Three capacitors of 3, 2 and 6 µF are connected in series with a battery of 10 V. Then charge on 3 µF capacitor will be

  • 10 µC

  • 12 µC

  • 14 µC

  • 5 µC



128.

The electric potential V is given as a function of distance x (m) by V = (5x2 + 10x − 9) volt. Value of electric field at x=l m is

  • 20 V/m

  • 6 V/m

  • 11 V/m

  • − 23 V/m



129.

If the energy of a 100 μF capacitor charged to 6 kV could all be used to lift a 5O kg mass, what would be the greatest vertical height through which mass could be raised?

  • 0.6 mm

  • 3.6 m

  • 1.2 mm

  • 12 m



130.

Three charged particles are initially in position-1. They are free to move and they come to position-2, after some time. Let U1 and U2 be the electrostatic potential energies in position-1 and 2 then

  • U1 = U2

  • U2  U1

  • U2 > U1

  • U1 > U2



1.png
curious learner
Do a good deed today
Refer a friend to Zigya