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CBSE

Subject

Physics

NEET Physics : Gravitation

Multiple Choice Questions

101.

Acceleration due to gravity:

decreases from the equator to poles
decreases from poles to the equator
is maximum at the centre of the earth
is maximum at the equator

102.

The distance between the sun and the earth be r then the angular momentum of the earth around the sun is proportional to :

$\sqrt{r}$
$r^{3 / 2}$
r
none of these

103.

The radius of orbit of a planet is two times that of the earth. The time period of the planet is :

4.2 T
2.8 T
5.6 T
8.4 T

104.

Two satellites A and B go around a planet P in circular orbits having radius 4 R and R respectively. If the speed of satellite A is 3v, then the speed of satellite B will be

6v
9v
3v
none of these

105.

The length of the second's pendulum is 1 m on earth. If the mass and diameter of a planet are doubled than that of earth. Then its length becomes

1 m
2 m
0.5 m
4 m

106.

According to Kepler's law, the time period of a satellite varies with its radius are as:

T² ∝ R³
T³ ∝ R²
$T^{2} \propto \frac{1}{R^{3}}$
$T^{3} \propto \frac{1}{R^{2}}$

107.

The radius of orbit of satellite of earth is R. Its kinetic energy is proportional to :

$\frac{1}{R}$
$\frac{1}{\sqrt{R}}$
R
$\frac{1}{R^{3 / 2}}$

108.

A particle falls towards earth from infinity. Its velocity on reaching the earth would be:

infinity
$\sqrt{2 gR}$
$2 \sqrt{gR}$
zero

109.

A body falls from a height h = 200 m. The ratio of distance travelled in each 2 sec, during t = 0 to t = 6 second of the journey is

1 : 4 : 9
1 : 2 : 4
1 : 3 : 5
1 : 2 : 3

110.

The period of oscillation of a simple pendulum of constant length at the surface of the earth is T. Its time period inside a mine will be :

can not be compared
equal to T
less than T
more than T

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