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NEET Physics : Oscillations

Multiple Choice Questions

121.

A particle of mass 10 g is executing simple harmonic motion with an amplitude of 0.5 m and periodic time of ( $π$ / 5) second. The maximum value of the force acting on the particle is

25 N
5 N
2.5 N
0.5 N

122.

A mass of 10 g moving horizontally with a velocity of 100 cm/s strikes a pendulum bob of mass 10 g. The two masses stick together. The maximum height reached by the system now is (g = 10 m/s²)

zero
5 cm
2.5 cm
1.25 cm

123.

A body executes simple harmonic motion under the action of force F₁ with a time period $\frac{4}{5}$ s. If the force is changed to F₂ it executes simple harmonic motion with time period $\frac{3}{5} s$ .If both forces F₁ and F₂ act simultaneously in the same direction on the body, its time period will be

$\frac{12}{25} s$
$\frac{24}{25} s$
$\frac{35}{24} s$
$\frac{15}{12} s$

124.

A simple pendulum of length l has a maximum angular displacement Q. The maximum kinetic energy of the bob is

mgl (1 - cosθ)
0.5 mgl
mgl
2 mgl

125.

A mass m is suspended from the two springs ofspring constants k₁ and k₂ as shown. The time period of vertical oscillations of the mass will be

$2 π \sqrt{(\frac{k_{1} + k_{2}}{m})}$
$2 π \sqrt{(\frac{m}{k_{1} + k_{2}})}$
$2 π \sqrt{\frac{m (k_{1} k_{2})}{k_{1} + k_{2}}}$
$2 π \sqrt{\frac{m (k_{1} + k_{2})}{(k_{1} k_{2})}}$

126.

If length of a simple pendulum increases by 300%, then its time period increases by

100 %
200 %
300 %
400 %

127.

A lift is ascending with an acceleration $\frac{g}{3}$ . A simple pendulum suspended from its ceiling oscillates with a period T. The period of oscillation of pendulum when the lift is stationary will be

$\frac{1}{\sqrt{3}} T$
T
2 T
$\frac{2}{\sqrt{3}} T$

128.

Potential energy of a particle at a distance x from mean position, which is executing simple harmonic motion

$\frac{1}{2} {mω}^{2} x^{2}$
zero
$m^{2} ωx$
$\frac{1}{2} m^{2} ω^{2} x^{2}$

129.

The period of vibration of a mass m suspended from a spring is 2 s. If along with it another mass of 2 kg is also suspended, the period of oscillation increases by ls. The mass m will be

2 kg
1 kg
1.6 kg
2.6 kg

130.

A man measure time period of a pendulum (T) in stationary lift. If the lift moves upward with acceleration g /4, then new time period will be

$\sqrt{\frac{2}{5}} T$
$\sqrt{\frac{5}{2}} T$
$\frac{\sqrt{5} T}{2}$
$\frac{2 T}{\sqrt{5}}$

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Subject

NEET Physics : Oscillations

Multiple Choice Questions