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NEET Physics : Oscillations

Multiple Choice Questions

141.

A particle starts SHM from the mean position. Its amplitude is a and total energy E. At one instant its kinetic energy is 3 $\frac{E}{4}$ · Its displacement at that instant is

$\frac{a}{\sqrt{2}}$
$\frac{a}{2}$
$\frac{a}{\sqrt{(\frac{3}{2})}}$
$\frac{a}{\sqrt{3}}$

142.

A spring of force constant k is cut into three equal parts. The force constant of each part would be

$\frac{k}{3}$
3k
k
2k

143.

Two springs are joined and attached to a mass of 16 kg. The system is then suspended vertically from a rigid support. The spring constant of the two springs are k₁ and k₂ respectively. The period of vertical oscillations of the system will be

$\frac{1}{8 π} \sqrt{k_{1} + k_{2}}$
$8 π \sqrt{\frac{k_{1} + k_{2}}{k_{1} k_{2}}}$
$\frac{π}{2} \sqrt{k_{1} - k_{2}}$
$\frac{π}{2} \sqrt{\frac{k_{1}}{k_{2}}}$

144.

A particle is executing linear simple harmonic motion of amplitude A. At what displacement is the energy of the particle half potential and half kinetic ?

$\frac{A}{4}$
$\frac{A}{2}$
$\frac{A}{\sqrt{2}}$
$\frac{A}{\sqrt{3}}$

145.

A spring of force constant k is cut into two equal halves. The force constant of each half is

$\frac{k}{\sqrt{2}}$
k
$\frac{k}{2}$
2k

146.

The time period of the second's hand of a watch is

1 h
1 s
12 h
1 min

147.

Two massless springs of force constants k₁ and k₂ are joined end to end. The resultant force constant k of the system is

$k = \frac{k_{1} + k_{2}}{k_{1} k_{2}}$
$k = \frac{k_{1} - k_{2}}{k_{1} k_{2}}$
$k = \frac{k_{1} k_{2}}{k_{1} + k_{2}}$
$k = \frac{k_{1} k_{2}}{k_{1} - k_{2}}$

148.

A particle of mass m is attached to three identical massless springs of spring constant k as shown in the figure. The time period of vertical oscillation of the particle is

$2 π \sqrt{\frac{m}{k}}$
$2 π \sqrt{\frac{m}{2 k}}$
$2 π \sqrt{\frac{m}{3 k}}$
$π \sqrt{\frac{m}{k}}$

149.

Two identical springs are connected to mass m as shown (k = spring constant). If the period of the configuration in (a) is 2s, the period of the configuration in (b) is

$\sqrt{2} s$
1 s
$\frac{1}{\sqrt{2}} s$
$2 \sqrt{2} s$

150.

A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration . Then its time period in second is

$\frac{1}{2 π \sqrt{3}}$
$2 π \sqrt{3}$
$\frac{2 π}{\sqrt{3}}$
$\frac{\sqrt{3}}{2 π}$

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NEET Physics : Oscillations

Multiple Choice Questions