Short Answer TypeCalculate the degree of dissociation (a) of acetic acid if its molar conductivity (Λm) is 39.05 S cm2mol–1. Given λo(H+) = 349.6 S cm2 mol–1 and λo(CH3COO–) = 40.9 S cm2 mol–1
The degree of dissociation is given by,
α = Λm / λo
here, α is the degree of dissociation,
Λm is the molar conductivity
λo is the molar conductivity at infinite dilution.
We have given
λo(H+) = 349.6 S cm2mol-1
and
λ0(CH3COO-) = 40.9 S cm2mol-1
then,
λoCH3COOH = λo CH3COO-+ λoH+
λoCH3COOH = 349.6 + 40.9 = 390.5
Now, degree of dissociation (α),
α = Λm /Λo
= 39.05 / 390.5 = 0.1
A 10% solution (by mass) of sucrose in water has the freezing point of 269.15 K.Calculate the freezing point of 10% glucose in water if freezing point of pure water is273.15 K.
Given : (Molar mass of sucrose = 342 g mol–1) (Molar mass of glucose = 180 g mol–1)
Calculate the mass of Ag deposited at cathode when a current of 2 amperes was passed through a solution of AgNO3 for 15 minutes.
(Given : Molar mass of Ag = 108 g mol–1 1F = 96500 C mol–1)
Why a solution of [Ni(H2O)6]2+ is green while a solution of [Ni(CN)4]2– is colourless? (At. no. of Ni = 28)
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