Write the vector equation of the following line:x - 53&

Subject

Mathematics

Class

CBSE Class 12

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 Multiple Choice QuestionsShort Answer Type

1.

If A =   cosα  - sinαsinα     cosα , then for what value of α is A an identity matrix?


2.

What is the principal value of cos-1 -32 ?


3.

What is the range of the function f(x) =  x - 1  x - 1 ?


4.

Find the minor of the element of second row and third column ( a23 ) in the following determinant:

  2  -3   56   0  41   5 -7  


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5.

If  1  23  4    3  12   5   =  7   11k   23 , then write the value of k.


6.

Evaluate: log xx dx


7.

What is the cosine of the angle which the vector 2 i^ + j^ + k  makes with y-axis?


8.

Write a vector of magnitude 15 units in the direction of vector  i^ - 2j^ + 2k


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9.

Write the vector equation of the following line:

x - 53 = y + 47 = 6 - z2


The given equation of line is  x - 53 = y + 47 = 6 - z2i.e. in standard form   x - 53 = y -(- 4 )7 = z - 6-2Comparing this equation with standard form   x - x1a = y - y1b = z - z1c

 

We get,   x1 = 5,    y1 = -4,   z1 = 6,    a = 3,     b = 7,   c = -2

 

Thus, the required line is parallel to the vector   3i^ + 7j^ - 2k and passes through the point ( 5, -4, 6 ).

The vector form of the line can be written as r = a + λ b, where λ is a constant.

Thus, the required equation is r =  5i^ - 4j^ + 6k  + λ  3i^ + 7j^ - 2k 


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10.

What is the degree of the following differential equation?

5x 5x dydx2 - d2ydx2 - 6y = log x


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