Subject

Chemistry

Class

ICSE Class 12

Pre Boards

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Sample Papers

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 Multiple Choice QuestionsShort Answer Type

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41.

Name the sulphide ore of Copper. Describe how pure copper is extracted from this ore.


Copper pyrites are concentrated by froth flotation process. In this process slurry of finely divided ore is taken in a large tank. Pine oil or eucalyptus oil is used as the frothing agent. Ethyl xanthate is added which is used as a collector (it increases the binding force between ore particles and forth). A mixture of all these things is agitated by the current of air and froth is formed. The froth being lighter than water floats over it. Particles of ore stick to it with the help of collector. The froth is separated and washed with water to get the concentrated ore.

(ii) Concentrated ore is converted into blister copper after roasting, smelting and bessemerisation.

Roasting: During roasting, the ore is heated in a reverberatory furnace in excess of air. The volatile impurities are removed during this process.

S + O2 → SO2

As + O2 → AsO2

The ore is converted into a mixture of sulphides.

2CuFeS2 + O2 →Cu2S + 2FeS + SO2

The sulphides are partially oxidised.

2Cu2S + 3O2 → 2Cu2O+ 2SO2

2FeS + 3O2 → 2FeO+ 2SO2

Smelting: In smelting, the roasted ore is mixed with coke and sand. It is done in a blast furnace. During smelting ore is heated in excess of air (02). As a result, the sulphides of copper and iron are converted into their oxides.

2Cu2S + 3O2→ 2Cu2O+ 2SO2

2FeS + 3O2 → 2FeO+ 2SO2

FeO reacts with sand (silica-SiO2) to form slag.

FeO + SiO2 → FeSiO3 Slag

Cu2O reacts with unoxidised FeS.

Cu2O + FeS → Cu2S + FeO

FeO forms slag. Slag floats over molten mass and is removed. The molten mass is called malte and it is a mixture of Cu2S, small quantity of FeS and FeO. Bessemerisation: The malte is taken out from the reverberatory furnace and is transferred to Bessemer converter. A blast of air and sand is passed into Bessemer converter and as a result, following reaction takes place.

2Cu2S + 3O2 → 2Cu2O + 2SO2

2FeS + 3O2 → 2FeO + 2SO2

Cu2O reacts with unreacted FeS and converts it into FeO which is removed in form of slag.
2Cu2S +FeS → Cu2S +FeO
FeO +SiO→FeSiO3

Cu2S and Cu2O react together to form blister copper which has about 98% Cu and has blister appearance due to the removal of SO2 from its surface in form of bubbles.

2Cu2O +Cu2S → 6Cu +SO2

(iii) Blister copper is converted into pure copper by electrolytic refining. Pure copper strips act as a cathode and impure copper acts as an anode. Acidic CuSO4 is used as an electrolyte when current is passed through this cell, pure copper deposits at the cathode and an equivalent amount of impure copper goes into solution from the anode. The impurities of Ag, Au and Sn deposit below anode as anode mud. The pure copper deposited at the cathode is scrapped off.


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42.

Calculate the emf and △Go for the cell reaction at 25oC:

Zn(s)|Zn2+(aq) ||Cd2+ (aq)| Cd(s)

Zn2+(aq) = (0.1 M)

Cd2+ (aq) = (0.01 m)

Given Eo Zn2+/Zn = -0.763 and Eo Cd2+/Cd = -0.403 V


43.

Define the following terms :

(1) Equivalent conductivity

(2) Corrosion of metals


44.

The specific conductivity of a solution containing 5 g of anhydrous BaCl2 (mol. wt = 208) in 1000 cm3 of a solution is found to be 0.0058 ohm–1cm–1. Calculate the molar and equivalent conductivity of the solution.


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45.

What is an electrochemical series? How is it useful in predicting whether a metal can liberate hydrogen from acid or not?


46.

Explain why :

Nitrogen does not form pentahalides


47.

Explain why :

 Helium is used for filling weather balloons.


48.

Explain why :

ICl is more reactive than I2


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49.

Draw the structures of the following :

(1) HClO4

(2) H3PO3


50.

Explain why :

Mercury loses its meniscus in contact with ozone.


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