Subject

Physics

Class

ICSE Class 12

Pre Boards

Practice to excel and get familiar with the paper pattern and the type of questions. Check you answers with answer keys provided.

Sample Papers

Download the PDF Sample Papers Free for off line practice and view the Solutions online.
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 Multiple Choice QuestionsShort Answer Type

21. An electric dipole is placed in a uniform external electric field EShow that the torque acting on the dipole is given by , where p is the dipole moment.
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22.

A potential difference of V volt is applied across a copper wire of length I and diameter d. How will the drift velocity be affected if

(i) V is double    (ii) I is doubled.

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23. State Biot-Savart law. Derive an expression for magnetic field at the centre of a circular current carrying coil of radius r. 
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24. Distinguish between diamagnetic and paramagnetic substance in terms of its relative permeability (μr) and magnetic susceptibility (x).
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25. A current of 4A flows in a coil when connected to a 12 V dc source. If the same coil is connected to a 12 V, 8 Hz ac source, a current of 2.4 A flows in the coil. Calculate the inductance of the coil.
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26. In the diagram given below (figure), find the current drawn from the battery: 




(i) just when the switch S is closed.

(ii) when sufficient time has elapsed after closing the switch.

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27.

Microwaves, X-rays, U.V. rays, infrared rays.

Which of the above electromagnetic waves has—

(i) the shortest wavelength.

(ii) the lowest frequency.

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28. Derive Snell’s law of refraction using Huygen’s principle.   
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29. In a Youngs double slit experiment with monochromatic light, fringes are obtained on a screen placed at a distance D from the slits. If the screen is moved by 5 x 10-2 m towards the slits, the change in the fringe width is 3 x 10-5 m If the distance between the slits is 10-3m, calculate the wavelength of the light used. 


Slit width, d = 10 -3 m

Fringe width, straight beta space equals space λD over straight d
If screen is moved by 5 x 10-2 m, towards screen, then fringe width 


straight beta apostrophe space equals space fraction numerator straight lambda space left parenthesis space straight D space minus space 5 space straight x space 10 to the power of negative 2 end exponent right parenthesis over denominator straight d end fraction

straight beta space minus space straight beta apostrophe space equals space straight lambda over straight d space left parenthesis space straight D space minus straight D space plus space 5 space straight x space 10 to the power of negative 2 end exponent right parenthesis

3 space straight x space 10 to the power of negative 5 end exponent space equals space straight lambda over 10 to the power of negative 3 end exponent space straight x space 5 space straight x space 10 to the power of negative 2 end exponent

rightwards double arrow space space straight lambda space equals space fraction numerator 3 space straight x space 10 to the power of negative 8 end exponent over denominator 5 space straight x space 10 to the power of negative 2 end exponent end fraction

rightwards double arrow space straight lambda space equals space 0.6 space straight x space 10 space to the power of negative 6 end exponent space straight m space
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30.

In a single slit diffraction pattern how does the angular width of central maximum change, when  

(i) the slit width is increased.

(ii) light of smaller wavelength is used.

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