By using Kirchoffs Law:
In ABEFA :
4 (I1 + I2) + 2I1 = 4
4I1 + 4I2 + 2/1 = 4
3 I1+ 2 I2 = 2 ...(1)
In BCDEB:
4 &(I1 + I2) + 12 I2 = 6
4 I1 + 16 I2 = 6
2I1 + 8I2 = 3 ...(2)
By solving equation (1) and (2)
I1 = 0.5 A
I2 = 0.25 A.
(i) the impedance of the circuit and
(ii) peak value of current in the circuit.