Geometry of ammonia molecule and the hybridisation of nitrogen in

Subject

Chemistry

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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1.

Geometry of ammonia molecule and the hybridisation of nitrogen involved in it are

  • sp3-hybridisation and tetrahedral geometry

  • sp3-hybridisation and distorted tetrahedral geometry

  • sp2-hybridisation and triangular geometry

  • None of the above


B.

sp3-hybridisation and distorted tetrahedral geometry

(i) Hybridisation = 1/2[no. of e- in valence shell of central atom + no. of monovalent atoms + charge on anion - charge on cation].

(ii) Shape or geometry of molecule depends on lone pair and bond pair of electrons present in it.

Hybridisation of N in NH3 = 1/2 (5+3+0-0) = 4

∴ sp3 3 hybridisation.

 It has 3 bond pair and 1 lone pair of electrons, so it has distorted tetrahedron shape.


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2.

Number of electrons in the valence orbit of nitrogen in an ammonia molecule is

  • 8

  • 5

  • 6

  • 7


3.

Be in BeCl2 undergoes

  • diagonal hybridisation

  • trigonal hybridisation

  • tetrahedral hybridisation

  • no hybridisation


4.

For the reaction

PCl5(g) → PCl3(g) + Cl2(g)

  • ΔH = ΔE

  • ΔH > ΔE

  • ΔH < ΔE

  • None of these


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5.

Which of the following is not a state function?

  • Internal energy

  • Enthalpy

  • Work

  • Entropy


6.

Enthalpy (H) is equal to

  • internal energy (E)

  • product of pressure (p) and volume (V) of gas

  • internal energy (E)+ pV

  • work (W) done by a system


7.

The pH of millimolar HCl is

  • 1

  • 3

  • 2

  • 4


8.

0.5 M ammonium benzoate is hydrolysed to 0.25 percent, hence, its hydrolysis constant is

  • 2.5 x 10-5

  • 1.5 x 10-4

  • 3.125 x 10-6

  • 6.25 x 10-6


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9.

Conjugate base of HSO4- is

  • SO42-

  • H2SO4

  • H3SO4+

  • None of these


10.

The pH of the solution 5 mL of M/5 HCl + 10 mL of M/10 NaOH is

  • 5

  • 3

  • 7

  • 8


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