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JEE Chemistry Solved Question Paper 2006

Multiple Choice Questions

1.
The relative lowering of vapour pressure of a dilute aqueous solution containing nonvolatile solute is 0.0125. The molality of the solution is about

0.70

0.50

0.90

0.80

0.70

Relative lowering of vapour pressure = mole fraction of solute (Raoult's law)

$\frac{p - p_{s}}{p} = X_{2} \frac{p - p_{s}}{p} = \frac{wM}{mW} where w = wt . of solute M = mol . wt . of solvent m = mol . wt . of solute W = wt . of solvent 0.0125 = \frac{wM}{mW} or \frac{w}{mW} = \frac{0.0125}{18} = 0.00070 Hence, molality = \frac{w}{mW} \times 1000 = 0.0007 \times 1000 = 0.70$

If the elevation in boiling point of a solution of 10g of solute (mol. wt. = 100) in 100g of water is ΔT_b, the ebullioscopic constant of water is

100T_b
ΔT_b
10T_b
10

An alloy of Pb-Ag weighing 1.08g was dissolved in dilute HNO₃ and the volume made to 100 mL. A silver electrode was dipped in the solution and the emf of the cell set up Pt(s), H₂(g)|H⁺(1M) || Ag⁺(aq)|Ag(s) was 0.62V. If E°_cell= 0. 80V what is the percentage of Ag in the alloy? [At 25°C, RT IF= 0.06].

The standard oxidation potentials of Zn, Cu, Ag and Ni electrodes are +0.76, 0.34, - 0.80 and +0.25 V respectively. Which of the following reaction will provide maximum voltage?