The electrons, identified by quantum numbers n and l,
(I) n = 3; l = 2; (II) n = 5; l = 0; (III) n = 4; l = 1; (IV) n = 4; l = 2; (V) n = 4; l = 0;
can be placed in order of increasing energy as-
I < V < III < IV < II
I < V < III < II < IV
V < I < III < II < IV
V < I < II < III < IV
The number of photons emitted per second by a 60 W source of monochromatic light of wavelength 663 nm is (h = 6 .63 × 10-34 Js)
4 × 10-20
1.5 × 1020
3 × 10-20
2 × 1020
Among the following species, identify the pair having same bond order CN-, O, NO+, CN+
CN- and O
O and NO+
CN- and NO+
CN- and CN+
Hydration of different ions in aqueous solution is an example of
ion-dipole interaction
ion-induced dipole interaction
dipole-dipole interaction
dipole-induced dipole interaction
When a sample of gas is compressed at constant temperature from 15 atm to 60 atm, its volume changes from 76 cm3 to 20.50 m3. Which of the following statements are possible explanations of this behaviour ?
1.The gas behaves non-ideally
2. The gas dimerises
3. The gas is adsorbed into the vessel walls
1, 2 and 3
1 and 2 only
2 and 3 only
1 only
The vapour pressure of two liquids X and Y are 80 and 60 Torr respectively. The total vapour pressure of the ideal solution obtained by mixing 3 moles of X and 2 moles of Y would be
68 Torr
140 Torr
48 Torr
72 Torr
'Hydride Gap' is referred to which region of the Periodic Table ?
Groups 3, 4 and 5
Groups 5, 6 and 7
Groups 4, 5 and 6
Groups 7, 8 and 9
Which of the following pairs of substances would give same gaseous product on reaction with water?
Na and Na2O2
Ca and CaH2
Ca and CaO
Ba and BaO2
B.
Ca and CaH2
Ca and CaH2 will give some gaseous product on reaction with water. The reaction is as follows-
Ca + H2O → CaO + H2
CaH2 + 2H2O → Ca(OH)2 + 2H2
The shape of XeF4 molecule and hybridisation of xenon in it are
tetrahedral and sp3
square planar and dsp2
square planar and sp3d2
octahedral and sp3d2
Energy released, when one atom of uranium undergoes nuclear fission according to the following reaction is (atomic mass of U = 235.060; n = 1.009; Ba= 143.881 and Kr = 89.94 7) about
92U235 + 0n1 → 56Ba144 + 36Kr90 + 2 0n1
235 MeV
208 MeV
931.5 MeV
5.33 x 1023 MeV