The amount of heat evolved when 500 cm3 of 0.1 M HCl is mixe

Subject

Chemistry

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

1.

The wave number of the spectral line in the emission spectrum of hydrogen will be equal to 89 times the rydberg's constant if the electron jumps from

  • n =3 to n =1

  • n = 10 to n=1

  • n=9 to n=1

  • n = 2 to n=1


2.

Consider the following gaseous equilibria with equilibrium constants K1 and K2 respectively.

SO2(g) + 12O2(g) SO3(g)2SO3(g)  2SO2 (g) + O2(g)The equilibrium constants are related as

  • K12 = 1K2

  • 2K1= K22

  • K2=2K12

  • K22=1K1


3.

Enthalpy of vaporization of benzene is + 35.3 kJ mol-1at its boiling point, 80C. The entropy change in the transition of the vapour to liquid at its boiling point in [JK-1mol-1] is

  • -441

  • -100

  • +441

  • +100


4.

Which one of the following conversions involve change in both hybridisation and shape?

  • CH4 → C2H6

  • NH3 → NH4+

  • BF3 → BF4-

  • H2O → H3O+


Advertisement
5.

In the reversible reaction,

A(s) + B(g) ⇌ C (g) + D(g) ΔG° = -350kJ

Which one of the following statements is true?

  • The entropy change is negative

  • Equilibrium constant is greater than one

  • The reaction should be instantaneous

  • The reaction is thermodynamically not feasible


Advertisement

6.

The amount of heat evolved when 500 cm3 of 0.1 M HCl is mixed with 200 cm3 of 0.2 M NaOH is

  • 2.292 kJ

  • 1.292 kJ

  • 0.292 kJ

  • 3.392 kJ


A.

2.292 kJ

HCl +         NaOH            NaCl + H2OIntinal moles500×0.11000     200 ×0.21000         0              0=0.05          =0.04final moles0.05-0.04        0                   0.04           0.04

In neutralisation of 1 mole of NaOH by 1 mole HCl, heat evolved = 57.3kJ
To neutralise 0.04 mole of NaOH by 0.04 mole of HCl,
heat evolved will be = 57.3 x 0.04kJ
                              = 2.292kJ


Advertisement
7.

During the adsorption of krypton on activated charcoal at low temperature.

  • ΔH > 0 and ΔS < 0

  • ΔH < 0 and ΔS < 0

  • ΔH > 0 and ΔS > 0

  • ΔH < 0 and ΔS < 0


8.

The set of quantum numbers for the outermost electron for copper in its ground state is

  • 4, 1, 1 +1/2

  • 3, 2, 2, +1/2

  • 4, 0, 0, +1/2

  • 4, 2, 2, +1/2


Advertisement
9.

Peroxide ion ......
(i) has five completely filled antibonding molecular orbitals
(ii) is diamagnetic
(iii) has bond order one
(iv) is isoelectronic with neon
Which one of these is correct?

  • (ii) and (iii)

  • (i), (ii) and (iv)

  • (i), (ii) and (iii)

  • (i) and (iv)


10.

A mixture of CaCl2 and NaCl weighing 4.44 g is treated with sodium carbonate solution to precipitate all the Ca2+ ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get 0.56 g of Cao. The percentage of NaCl in the mixture (atomic mass of Ca = 40) is

  • 75

  • 30.6

  • 25

  • 69.4


Advertisement