4.9 g of H2SO4 is present in 100 mL solution. The molarity and no

Subject

Chemistry

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

1.

The standard enthalpy of vapourisation Δvap H° for water at 100°C is 40.66 kJ mol-1. The internal energy of vapourisation of water 100°C (in kJ mol-1) is (assume water vapour to behave like an ideal gas).

  • + 4376

  • +40.66

  • +37.56

  • None of these


2.

The wavelength of associated wave of a particle moving with a speed of one-tenth that of light is 7Å. The particle must be

  • electron

  • proton

  • nanoparticle

  • photon


3.

Which mathematical statement did not prove false?

  • E= hv

  • R=me48ε02h3c

  • R=n12n22v(n12-n22)c

  • mvr= nh2π


4.

The bond order in CN- ion is

  • 2.5

  • 3

  • 2

  • 3.5


Advertisement
5.

Np93239 is a β- emitter, but the product is also radioactive and give 235U. Which particles(s) is/ are emitted by the product?

  • 4 neutrons

  • 4 protons

  • 4 protons and 2electrons

  • 2 neutrons and 2 protons


6.

If the adsorption of a gas on solid metal surface is spontaneous and exothermic, then

  • H increases

  • S increases

  • G increases

  • S decreases


7.

What is the solubility of silver bromide in one litre of 0.4 molar NH3 solution (K =10x108)?

  • 80 × 10-6 mol

  • 2.8 × 10-3 mol

  • 115 × 10-3 mol

  • 0.98 g


8.

Which expression has no physical significance?

  • GTp

  • GpT

  • (G)Tp

  • (G)pT


Advertisement
Advertisement

9.

4.9 g of H2SO4 is present in 100 mL solution. The molarity and normality of the solution will be

  • Molarity = 1M, Normality= 0.5N

  • Molarity = 1M, Normality= 0.25N

  • Molarity = 0.5M, Normality= 1N

  • Molarity = 2M, Normality= 3N


C.

Molarity = 0.5M, Normality= 1N

Given, Mass of H2SO4(w) = 49GVolume of solution (V) = 100 mL Molar mass (M) = 98Molarity(C) =w×1000M ×V   C =4998×1000100Molarity = 0 .5 mol/L ,0 .5 MNormality (N) = Z × molarity (C) Where, Z = equivalent factorFor H2SO4(Z=2) = 0.5MNormality =2 ×0. 5 = 1 N


Advertisement
10.

0.0833 mole of a carbohydrate of empirical formula CH2O contains 1.00 g of hydrogen. The molecular formula of the carbohydrate is.

  • C5H10O5

  • C3H4O3

  • C12H22O11

  • C6H12O6


Advertisement