Glucose on prolonged heating with HI gives from Chemistry JEE Ye

Subject

Chemistry

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

21.

The oxidation states of Cr in [Cr(H2O)6]Cl3,[Cr(C6H6)2], and K2[Cr(CN)2 (O)2(O2)(NH3)] respectively are :

  • +3, +2, and +4

  • +3, 0, and +6

  • +3, 0, and +4

  • +3, +4, and +6


22.

Which of the following compounds will be suitable for Kjeldah1’s method for nitrogen estimation?


Advertisement

23.

Glucose on prolonged heating with HI gives

  • 6-iodohexanal

  • n-Hexane

  • 1-Hexene

  • Hexanoic acid


B.

n-Hexane

The reaction of glucose with HI giving n-hexane suggests that all the six carbon atoms are linked in a straight chain, as shown in the reaction given below:


Advertisement
24.

The increasing order of basicity of the following compounds is:

  • (d) < (b) < (a) < (c)

  • (a) < (b) < (c) < (d)

  • (b) < (a) < (c) < (d)

  • (b) < (a) < (d) < (c)


Advertisement
25.

Phenol reacts with methyl chloroformate in the presence of NaOH to form product A. A reacts with Br2 to form product B. A and B are respectively:


26.

The major product formed in the following reaction is:


27.

Phenol on treatment with CO2 in the presence of NaOH followed by acidification produces compound X as the major product. X on treatment with (CH3CO)2O in the presence of catalytic amount of H2SO4 produces:


28.

The major product of the following reaction is,


Advertisement
29.

The compound that does not produce nitrogen gas by the thermal decomposition is

  • (NH4)2SO4

  • Ba(N3)2

  • (NH4)2Cr2O7

  • NH4NO2


30.

Which of the following salts is the most basic in aqueous solution?

  • Pb(CH3COO)2

  • Al(CN)3

  • CH3COOK

  • FeCl3


Advertisement