The element having greatest difference between its first and seco

Subject

Chemistry

Class

JEE Class 12

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

1.

Among the following, the set of parameters that represents path functions, is:

(A) q+w

(B) q

(C) w

(D) H-TS

  • A, B and C

  • B, C and D

  • B and C

  • A and D


2.

The degenrate orbitals of [Cr(H2O)6]3+ are

  • dyz and dz2

  • dx2 and dxz

  • dxz and dyz

  • dx2-y2 and dxy


Advertisement

3.

The element having greatest difference between its first and second ionization energies, is

  • K

  • Ca

  • Ba

  • Sc


A.

K

Among the given options, K has greatest difference between its first and second ionisation energies.


Advertisement
4.

The standard Gibbs energy for the given cell reaction in kJ mol-1 at 298 K is:

Zn (s) + Cu2+ (aq) → Zn2+ (aq) + Cu (s), E° = 2V at 298 K

  • -192

  • 384

  • -384

  • 192


Advertisement
5.

Among the following, the molecule expected to be stabilized by anion formation is: 

C2, O2, NO and F2

  • NO

  • C2

  • F2

  • O2


6.

For any given series of spectral lines of atomic hydrogen, let v = vmax - vmin be the difference in maximum and minimum frequencies in cm-1. The ratio vBalmer is:

  • 4 : 1

  • 9 : 4

  • 5 : 4

  • 27.5


7.

For a reaction, N2 (g) + 3H2 (g) → 2NH3 (g); Identify dihydrogen (H2) as a limiting reagent in the following reaction mixtures.

  • 35 gm of N2 + 8 gm of H2

  • 28 gm of N2 + 6 gm of H2

  • 56 gm of N2 + 10 gm of H2

  • 14 gm of N2 + 4 gm of H2


8.

Liquid ‘M’ and liquid ‘N’ form an ideal solution. The vapour pressures of pure liquids ‘M’ and ‘N’ are 450 and 700mm Hg, respectively, at the same temperature. Then correct statement is:

(xM = Mole fraction of 'M' is solution; xN = Mole fraction of 'N' in solution; yM = Mole fraction of 'M' in vapour phase; yN = Mole fraction of 'N' in vapour phase)

  • xMxN < yMyN

  • xMxN = yMyN

  • xMxN > yMyN

  • (xM - yM) < (xN - yN)


Advertisement
9.

The correct IUPAC name of following compound 

  • 2-methyl–5-nitro-1-chlorobenzene

  • 2-chloro–1-methyl-4-nitrobenzene

  • 5-chloro–4–methyl–1–nitrobenzene

  • 3-chloro–4–methyl–1–nitrobenzene


10.

The organic compound that gives following qualitative analysis is:
Test Inference
a. Dil. HCl Insoluble
b. NaOH solution Soluble
c. Br2/ water Decolourization


Advertisement