is equal to
πab
π22ab
π2ab
D.
Let I = ∫0πxdxa2cos2x + b2sin2xdx ...i I = ∫0ππ - xa2cos2π - x + b2sin2π - xUsing ∫0afxdx = ∫0afa - xdxor I = ∫0ππ - xa2cos2x + b2sin2xdx ...iiAdding Eqs. (i) and (ii),2I = ∫0πx + π - xa2cos2x + b2sin2x = π∫0πdxa2cos2x + b2sin2x = 2π∫0π2dxa2cos2x + b2sin2x∵ ∫02af(x)dx = 2∫0afxdx, = 2π∫0π2xa2 + b2tan2x
Now, put tan x = t∴ dx = dtsec2x = 2π∫0∞dta2 + b2t2 = 1b2 × 2π∫0∞dta2b2 + t2 = 2πb2 . batan-1bta = 2πabtan-1∞ - tan-10 = 2πabπ2 - 0 = 2πab × π2 = π2ab
The differential equation for which sin-1(x) + sin-1(y) = c is given by
1 - x2dy + 1 - y2dx = 0
1 - x2dx + 1 - y2dy = 0
1 - x2dx - 1 - y2dy = 0
1 - x2dy - 1 - y2dx = 0
∫ex1 + sinx1 + cosxdx is equal to
exsec2x2 + c
extanx2 + c
exsecx2 + c
extanx + c
∫1 + sinx4dx is equal to
8sinx8 + cosx8 + C
8sinx8 - cosx8 + C
8cosx8 - sinx8 + C
18sinx8 - cosx8 + C
∫0∞xdx1 + x1 + x2 is equal to
π2
0
1
π4
If In = ∫logxndx, then In + nIn - 1 is equal to
xlogxn
nlogxn
logxn - 1
The area included between the parabolas x2 = 4y and y2 = 4x is (in square units)
43
13
163
83