If c1, c2, c3, c4, c5 and c6 are constants, then the order of the differential equation whose general solution is given by y = c1 cos(x + c2) + c3 sin(x + c4) + c5ex + c6, is
6
5
4
3
y = 2e2x - e- x is solution of the differential equation
y2 + y1 + 2y = 0
y2 - y1 + 2y = 0
y2 + y1 = 0
y2 - y1 - 2y = 0
D.
y2 - y1 - 2y = 0
Given that
y = 2e2x - e-x
On differentiating wrt x, we get
y1 = 4e2x + e- x
Now, on again differentiating wrt x, we get
y3 = 8e2x - e- x
Now, y2 - y1 - 2y
= 8e2x - e- x - 4e2x - e- x - 4e2x + 2e- x
= 0