The locus of a point P which moves such that 2PA = 3PB, where A(0, 0) and B(4,- 3) are points, is
5x2 - 5y2 - 72x + 54y + 225 = 0
5x2 + 5y2 - 72x + 54y + 225 = 0
5x2 + 5y2 + 72x - 54y + 225 = 0
5x2 + 5y2 - 72x - 54y - 225 = 0
The points P is equidistant from A(1, 3), B (- 3, 5) and C(5, - 1), then PA is equal to
5
25
D.
Perpendicular bisector of A (1, 3) andB(- 3, 5) is,
2x(x1 - x2) + 2y(y1 - y2) =
Similarly, perpendicular bisector of A (1, 3) and C (5, - 1) is
Point of intersection of Eqs. (i) and (ii), is P = (- 8, - 10).
Then, the distance between P and A is,