The equation of sphere concentric with the sphere x2 + y2 + z2 - 4x - 6y - 8z - 5 = 0 and which passes through the origin, is
x2 + y2 + z2 - 4x - 6y - 8z = 0
x2 + y2 + z2 - 6y - 8z = 0
x2 + y2 + z2 = 0
x2 + y2 + z2 - 4x - 6y - 8z - 6 = 0
If the lines and intersect, then the value of k, is
-
B.
We have the lines
...(i)
...(ii)
Let a point (2r + 1, 3r - 1, 4r + 1) be on the line Eq. (i). If this is an intersection point of both the lines, then it will lie on Eq. (ii), also
...(iii)
Taking first and third part of Eq. (iii), we get
2r - 2 = 4r + 1
Taking second and third part of Eq. (iii), we get
3r - 1 - k = 8r + 2
3r - 1 - k - 8r - 2 = 0
If two circles 2x2 + 2y2 - 3x + 6y + k = 0 and x2 + y2 - 4x + 10y + 16 = 0 cut orthagobally then, value of k is
41
14
4
1
If B is a non-singular matrix and A is a square matrix, then det (B-1AB) is equal to
det(A-1)
det(B-1)
det(A)
det(B)
If f(x), g(x) and h(x) are three polynomials of degree 2 and , then is a polynomials of degree
2
3
0
atmost 3