The equation of sphere concentric with the sphere x2 + y2 + z2 - 4x - 6y - 8z - 5 = 0 and which passes through the origin, is
x2 + y2 + z2 - 4x - 6y - 8z = 0
x2 + y2 + z2 - 6y - 8z = 0
x2 + y2 + z2 = 0
x2 + y2 + z2 - 4x - 6y - 8z - 6 = 0
If two circles 2x2 + 2y2 - 3x + 6y + k = 0 and x2 + y2 - 4x + 10y + 16 = 0 cut orthagobally then, value of k is
41
14
4
1
C.
4
We have given two circles are
2x2 + 2y2 - 3x + 6y + k = 0
Since, general equation of circle is
x2 + y2 + 2gx + 2fy + c = 0 ...(iii)
Therefore, comparing Eqs. (i) and (ii) with Eq. (iii), we get
If B is a non-singular matrix and A is a square matrix, then det (B-1AB) is equal to
det(A-1)
det(B-1)
det(A)
det(B)
If f(x), g(x) and h(x) are three polynomials of degree 2 and , then is a polynomials of degree
2
3
0
atmost 3