If the vectors $\overrightarrow{\mathrm{a}} = 2\hat{\mathrm{i}} + \hat{\mathrm{j}} + 4\hat{\mathrm{k}},$ $\overrightarrow{\mathrm{b}} = 4\hat{\mathrm{i}} - 2\hat{\mathrm{j}} + 3\hat{\mathrm{k}}$ and $\overrightarrow{\mathrm{c}} = 2\hat{\mathrm{i}} - 3\hat{\mathrm{j}} - \mathrm{\lambda }\hat{\mathrm{k}}$ are coplanar, then the value of $\mathrm{\lambda }$ is equal to

• 2

• 1

• 3

• - 1

Let A(1, - 1, 2) and B (2, 3, - 1) be two points. If a point P divides AB internally in the ratio 2 : 3, then the position vector of P is

• $\frac{1}{\sqrt{5}}\left(\hat{\mathrm{i}} + \hat{\mathrm{j}} + \hat{\mathrm{k}}\right)$

• $\frac{1}{\sqrt{3}}\left(\hat{\mathrm{i}} + 6\hat{\mathrm{j}} + \hat{\mathrm{k}}\right)$

• $\frac{1}{\sqrt{3}}\left(\hat{\mathrm{i}} + \hat{\mathrm{j}} + \hat{\mathrm{k}}\right)$

• $\frac{1}{5}\left(7\hat{\mathrm{i}} + 3\hat{\mathrm{j}} + 4\hat{\mathrm{k}}\right)$

If the scalar product of the vector $\hat{\mathrm{i}} + \hat{\mathrm{j}} + 2\hat{\mathrm{k}}$ with the unit vector along $\mathrm{m}\hat{\mathrm{i}} + 2\hat{\mathrm{j}} + 3\hat{\mathrm{k}}$ is equal to 2, then one of the values of m is

• 3

• 4

• 5

• 6

A plane makes intercepts a, b, cat A, B, C on the coordinate axes respectively. If the centroid of the $∆$ABC is at (3, 2, 1), then the equation of the plane is

• x + 2y + 3z = 9

• 2x - 3y - 6z = 18

• 2x + 3y + 6z = 18

• 2x + y + 6z = 18

35.

If the plane 3x + y + 2z + 6 = 0 is parallel to the line $\frac{3\mathrm{x} - 1}{2\mathrm{b}} = 3 - \mathrm{y} = \frac{\mathrm{z} - 1}{\mathrm{a}}$, then the avlue of 3a + 3b is

• $\frac{1}{2}$

• $\frac{3}{2}$

• 3

• 4

The equation of the line passing through the point (3, 0,- 4) and perpendicular to the plane 2x - 3y + 5z - 7 = 0 is

• $\frac{\mathrm{x} - 2}{3} = \frac{\mathrm{y}}{- 3} = \frac{\mathrm{z} + 4}{5}$

• $\frac{\mathrm{x} - 3}{2} = \frac{\mathrm{y}}{- 3} = \frac{\mathrm{z} - 4}{5}$

• $\frac{\mathrm{x} - 2}{3} = \frac{- \mathrm{y}}{3} = \frac{\mathrm{z} + 4}{5}$

• $\frac{\mathrm{x} + 3}{2} = \frac{\mathrm{y}}{3} = \frac{\mathrm{z} - 4}{5}$

The plane $\overrightarrow{\mathrm{r}} = \mathrm{s}\left(\hat{\mathrm{i}} + \hat{\mathrm{j}} - 4\hat{\mathrm{k}}\right)$ $+ \mathrm{t}\left(3\hat{\mathrm{i}} +4 \hat{\mathrm{j}} - 4\hat{\mathrm{k}}\right)$ + $\left(1 - \mathrm{t}\right)\left(2\hat{\mathrm{i}} - 7\hat{\mathrm{j}} - 3\hat{\mathrm{k}}\right)$ is parallel to the line

• $\overrightarrow{\mathrm{r}} = \left(- \hat{\mathrm{i}} + \hat{\mathrm{j}} - \hat{\mathrm{k}}\right) + \mathrm{t}\left(- \hat{\mathrm{i}} - 2\hat{\mathrm{j}} + 4\hat{\mathrm{k}}\right)$

• $\overrightarrow{\mathrm{r}} = \left(- \hat{\mathrm{i}} + \hat{\mathrm{j}} - \hat{\mathrm{k}}\right) + \mathrm{t}\left( \hat{\mathrm{i}} - 2\hat{\mathrm{j}} + 4\hat{\mathrm{k}}\right)$

• $\overrightarrow{\mathrm{r}} = \left(\hat{\mathrm{i}} + \hat{\mathrm{j}} - \hat{\mathrm{k}}\right) + \mathrm{t}\left(- \hat{\mathrm{i}} - 4\hat{\mathrm{j}} + 7\hat{\mathrm{k}}\right)$

• $\overrightarrow{\mathrm{r}} = \left(- \hat{\mathrm{i}} + \hat{\mathrm{j}} - 3\hat{\mathrm{k}}\right) + \mathrm{t}\left(2\hat{\mathrm{i}} + 6\hat{\mathrm{j}} - 8\hat{\mathrm{k}}\right)$

The distance between the line $\overrightarrow{\mathrm{r}} = \left(2\hat{\mathrm{i}} + 2\hat{\mathrm{j}} - \hat{\mathrm{k}}\right) + \mathrm{\lambda }\left(2\hat{\mathrm{i}} + \hat{\mathrm{j}} - 2\hat{\mathrm{k}}\right)$ and the plane $\overrightarrow{\mathrm{r}} . \left(\hat{\mathrm{i}} + 2\hat{\mathrm{j}} + 2\hat{\mathrm{k}}\right)$ = 10 is equal to

• 5

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• 3

• 2

Equation of the plane passing through t intersection of the planes x + y + z = 6 and 2x + 3y + 4z + 5 = 0 and the point (1, 1, 1)

• 20x + 23y + 26z - 69 = 0

• 31x + 45y + 49z + 52 = 0

• 8x + 5y + 2z - 69 = 0

• 4x + 5y + 6z - 7 = 0

The equation of the plane containing the line $\frac{\mathrm{x} - 1}{2}$ = $\frac{\mathrm{y} + 1}{- 1}$ = $\frac{\mathrm{z}}{3}$ and $\frac{\mathrm{x}}{2}$ = $\frac{\mathrm{y} - 2}{- 1}$ = $\frac{\mathrm{z} + 1}{3}$ is

• 8x - y + 5z - 8 = 0

• 8x + y - 5z - 7 = 0

• x - 8y + 3z + 6 = 0

• 8x + y - 5z + 7 = 0