If are the roots of the equation x2 + px + q = 0, where are real, then the roots of the equation (p2 - 4q)(p2x2 + 4px) - 16q = 0 are
The remainder obtained when 1! + 2! + ... + 95! is divided by 15 is
14
3
1
0
B.
3
Since, 1! = 1, 2! = 2, 3! = 6, 4! = 24, 5! = 120
Since, all terms from 5! onwards are divisible by 15 and 1! + 2! + 3! + 4! = 33
The required remainder after dividing by 15 will be 3
Two decks of playing cards are well shuffled and 26 cards are randomly distributed to a player. Then, the probability that the player gets all distinct cards is
An um contains 8 red and 5 white balls. Three balls are drawn at random. Then, the probability that balls of both colours are drawn is
Let R be the set of real numbers and the functions f : R ➔ R and g : R ➔ R be defined by f(x) = x2 + 2x - 3 and g(x) = x + 1. Then, the value of x for which f(g(x)) = g(f(x)) is
- 1
0
1
2
If a, b and c are in arithmetic progression, then the roots of the equation ax - 2bx + c = 0 are