The points on the graph y = x3 - 3x at which the tangent is parallel to x-axis are
(2, 2) and (1, - 2)
(- 1, 2) and (- 2, - 2)
(2, 2) and (- 1, 2)
(1, - 2) and (- 1, 2)
The slope of the normal to the curve y2 - xy - 8 = 0 at the point (0, 2) is equal to
- 3
- 6
3
6
B.
- 6
Given curve is y3 - xy - 8 = 0
On differentiating w.r.t. x, we get
If the straight line y - 2x+ 1 = 0 is the tangent to the curve xy + ax + by = 0 at x = i, then the values of a and b are respectively
1 and 2
1 and - 1
- 1 and 2
1 and - 2