Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

Let n be a positive even integer. If the ratio of the largest coefficient and the 2nd largest coefficient in the expansion of (1 + x)n is 11 : 10. Then, the number of terms in the expansion of (1 + x)n is

  • 20

  • 21

  • 10

  • 11


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42.

Five numbers are in AP with common difference  0. If the 1st, 3rd and 4th terms are in GP, then

  • the 5th term is always 0.

  • the 1st term is always 0.

  • the middle term is always 0

  • the middle term is always - 2.


A.

the 5th term is always 0.

Let the tine number is in AP are

(a - 2d), (a - d), a, (a + d), (a + 2d)

where, d  0

Given, 1st, 3rd and 4th terms are in GP.

             a2 = a - 2da + d             a2 = a2 - 2ad + ad - 2d2 2d2 + ad = 0 d2d + a = 0               d  0     a + 2d = 0              a = - 2d

Hence, terms are - 4d, - 3d, -2d, -d, 0.

Thus, The fifth term is always 0.


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43.

The sum of series

11 × 2C025 + 12 × 3C125 + 13 × 4C225 + ... + 126 × 27C2525

is

  • 227 - 126 × 27

  • 227 - 2826 × 27

  • 12226 + 126 × 27

  • 226 - 152


44.

If P, Q and R are angles of an isosceles triangle and P = π2,  then the value of

cosP3 - isinP33 + cosQ + isinQcosR - isinR        + cosP - isinPcosQ - isinQcosR - isinR

  • i

  • - i

  • 1

  • - 1


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45.

Let f : R  R  be such that f is injective and f(x) f(y) = f(x + y) for all x, y if f(x), f(y) and f(z) are in GP, then x, y and z are in

  • AP always

  • GP always

  • AP depending on the values of x, y and z

  • GP depending on the values of x, y and z


46.

The number of solutions of the equation

12log3x + 1x +5 + logex + 52 = 1

  • 0

  • 1

  • 2

  • infinite


47.

If P = 1 + 12 × 2 + 13 × 22 + ... and Q = 11 × 2 + 13 × 4 + 15 × 6 + ...,

then

  • P = Q

  • 2P =Q

  • P = 2Q

  • P = 4Q


48.

The area of the region bounded by the parabola y = x2 - 4x + 5 and the straight line y= x + l is

  • 12

  • 2

  • 3

  • 92


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49.

If fx = sinx + 2cos2x, π4  x  3π4. Then, f attains its

  • minimum at x = π4

  • maximum at x = π2

  • minimum x = π2

  • mamum at x = sin-114


50.

A line passing through the point of intersection of x + y = 4 and x - y = 2 makes an angle tan-134 with the x-axis. It intersects the parabola y2 = 4(x - 3) at points (x1, y1) and (x2, y2) respectively. Then, x1 - x2 is equal to

  • 169

  • 329

  • 409

  • 809


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