Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

Let n be a positive even integer. If the ratio of the largest coefficient and the 2nd largest coefficient in the expansion of (1 + x)n is 11 : 10. Then, the number of terms in the expansion of (1 + x)n is

  • 20

  • 21

  • 10

  • 11


42.

Five numbers are in AP with common difference  0. If the 1st, 3rd and 4th terms are in GP, then

  • the 5th term is always 0.

  • the 1st term is always 0.

  • the middle term is always 0

  • the middle term is always - 2.


43.

The sum of series

11 × 2C025 + 12 × 3C125 + 13 × 4C225 + ... + 126 × 27C2525

is

  • 227 - 126 × 27

  • 227 - 2826 × 27

  • 12226 + 126 × 27

  • 226 - 152


44.

If P, Q and R are angles of an isosceles triangle and P = π2,  then the value of

cosP3 - isinP33 + cosQ + isinQcosR - isinR        + cosP - isinPcosQ - isinQcosR - isinR

  • i

  • - i

  • 1

  • - 1


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45.

Let f : R  R  be such that f is injective and f(x) f(y) = f(x + y) for all x, y if f(x), f(y) and f(z) are in GP, then x, y and z are in

  • AP always

  • GP always

  • AP depending on the values of x, y and z

  • GP depending on the values of x, y and z


46.

The number of solutions of the equation

12log3x + 1x +5 + logex + 52 = 1

  • 0

  • 1

  • 2

  • infinite


47.

If P = 1 + 12 × 2 + 13 × 22 + ... and Q = 11 × 2 + 13 × 4 + 15 × 6 + ...,

then

  • P = Q

  • 2P =Q

  • P = 2Q

  • P = 4Q


48.

The area of the region bounded by the parabola y = x2 - 4x + 5 and the straight line y= x + l is

  • 12

  • 2

  • 3

  • 92


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49.

If fx = sinx + 2cos2x, π4  x  3π4. Then, f attains its

  • minimum at x = π4

  • maximum at x = π2

  • minimum x = π2

  • mamum at x = sin-114


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50.

A line passing through the point of intersection of x + y = 4 and x - y = 2 makes an angle tan-134 with the x-axis. It intersects the parabola y2 = 4(x - 3) at points (x1, y1) and (x2, y2) respectively. Then, x1 - x2 is equal to

  • 169

  • 329

  • 409

  • 809


B.

329

Given lines are x + y = 4 and x - y = 2

On solving these lines, we get

x = 3 and y = 1

Now, the equation of line which passes through the intersection point (3, 1) having slope,

θ = tan-134 is y - 1 = 34x - 3                        4y - 4 = 3x - 9                       3x - 4y = 5

Now tor the intersection point of the line (i) with parabola y2 = 4(x - 3). Put y = 3x - 54, then we get

                  3x - 5216 = 4x - 3   9x2 + 25 - 30x = 64x - 192 9x2 - 94x + 217 = 0    x = 94 ± 8836 - 781218           = 94 ± 3218 = 12818 or 6218  x1 = 213 = 7and x2 = 319 x1 - x2 = 7 - 319 = 329 = 329


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