If tan-1x2 + cot-1x2 = 5π28, then x i

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

The value of the expression 1 . (2 - w)(2 - w2) + 2 . (3 - w)(3 - w2) + ... + (n - 1)(n - w2), where w is an imaginary cube root of unity is

  • nn + 122

  • nn + 122 - n

  • nn + 122 + n

  • None of these


2.

1 = xbbaxbaax and 2 = xbax are the given determinants, then

  • 1 = 322

  • ddx1 = 32

  • ddx1 = 322

  • 1 = 3232


3.

If A and B are square matrices of the same order and A is non-singular, then for a positive integer n, (A-1BA)n is equal to

  • A-nBnAn

  • AnBnA-n

  • A-1BnA

  • n(A-1BA)


4.

The function f(x) = x2a,             0  x < 1a,                  1  x < 22b2 - 4bx2, 2  x <  is continuous for 0  x < ,then the most suitable values of a and b are

  • a = 1, b = - 1

  • a = - 1, b = 1 + 2

  • a = - 1, b = 1

  • None of the above


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5.

If f(x) = 1,                  x < 01 + sinx,    0  x < π2,then at x = 0 the derivative f'(x) is

  • 1

  • 0

  • infinite

  • not defined


6.

Let P(x) = a0 + a1x2 + a2x2 + a3x6 + ... + anx2n be a polynomial in a real variables with 0 < a0 < a1 < a2 < .... < an. The function P(x) has

  • neither a maxima nor a minima

  • only one maxima

  • both maxima and minima

  • only one minima


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7.

If tan-1x2 + cot-1x2 = 5π28, then x is equal to

  • - 1

  • 1

  • 0

  • None of these


A.

- 1

We have, tan-1x2 + cot-1x2 = 5π28 tan-1x + cot-1x2 - 2tan-1x . cot-1x = 5π28 π22 - 2tan-1xπ2 - tan-1x = 5π28 - 3π28 = πtan-1x - 2tan-1x2 2tan-1x2 - πtan-1x - 3π28 = 0 tan-1x = π2 tan-1x = 3π4 tan-1x = - π4             x = - 1


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8.

α32csc212tan-1αβ + β32sec21212tan-1βα is equal to

  • α - βα2 + β2

  • α + βα2 - β2

  • α + βα2 + β2

  • None of the above


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9.

dx9 + 16sin2x is equal to

  • 13tan-13tanx5 + c

  • 15tan-1tanx15 + c

  • 115tan-1tanx5 + c

  • 115tan-15tanx3 + c


10.

x2dxxsinx + cosx2 is equal to

  • sinx + cosxxsinx + cosx + c

  • xsinx - cosxxsinx + cosx + c

  • sinx - xcosxxsinx + cosx + c

  • None of these


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