If the vertices of a· triangle are A(0, 4, 1), B(2, 3, - 1) and C(4, 5, 0), then the orthocentre of ABC, is
(4, 5, 0)
(2, 3, - 1)
(- 2, 3, - 1)
(2, 0, 2)
The normals at three points· P,Q and R of the parabola y2 = 4ax meet at (h, k). The centroid of the PQR lies on
x = 0
y = 0
x = - a
y = a
B.
y = 0
We know that, the sum of ordinates of feet of normals drawn from a point to the parabola, y2 = 4ax is always zero.
Now, as normals at three points P,Q and R of parabola y2 = 4ax meet at (h, k):
The normals from (h,k) to y2 = 4ax meet the parabola at P, Q and R.
y-coordinates y1, y2, y3 of these points P,Q and R will be zero
y-coordinate of the centroid of POR
i. e. ,
Hence, centroid lies on y = 0.
The minimum area of the triangle formed by any tangent to the ellipse ( x2/a2 ) + ( y2/b2 ) = 1 with the coordinate axes is
a2 + b2
( a + b )2/2
ab
( a - b )2/2
If the line lx + my - n = 0 will be a normal to the hyperbola, then , where k is equal to
n
n2
n3
None of these