If the line lx + my - n = 0 will be a normal to the hyperbola, th

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

If the vertices of a· triangle are A(0, 4, 1), B(2, 3, - 1) and C(4, 5, 0), then the orthocentre of ABC, is

  • (4, 5, 0)

  • (2, 3, - 1)

  • (- 2, 3, - 1)

  • (2, 0, 2)


2.

If r = 2r - 1Crm1m2 - 12mm + 1sin2m2sin2msin2m + 1, then the value of r = 0mr

  • 1

  • 0

  • 2

  • None of these


3.

Two lines x - 12 = y + 13 = z - 14 and x - 31 = y - k2 = z intersect at a point, if k is equal to

  • 29

  • 12

  • 92

  • 16


4.

The statement p  q  ~ p  q is

  • tautology

  • contradiction

  • Neither (a) nor (b)

  • None of these


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5.

If x + iy = 32 + cosθ + isinθ,  then x2 + y2 is equal to

  • 3x - 4

  • 4x - 3

  • 4x + 3

  • None of these


6.

The negation of ~ p  q  p  ~ q is

  • p  ~ q  ~ p  q

  • ~ p   q  ~ p  q

  • p  ~ q  ~ p  q

  • p  ~ q  p  ~ q


7.

The normals at three points· P,Q and R of the parabola y2 = 4ax meet at (h, k). The centroid of the PQR lies on

  • x = 0

  • y = 0

  • x = - a

  • y = a


8.

The minimum area of the triangle formed by any tangent to the ellipse ( x2/a2 ) + ( y2/b2 ) = 1 with the coordinate axes is

  • a2 + b2

  • ( a + b )2/2

  • ab

  • ( a - b )2/2


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9.

If the line lx + my - n = 0 will be a normal to the hyperbola, then a2l2 - b2m2 = a2 + b22k, where k is equal to

  • n

  • n2

  • n3

  • None of these


B.

n2

The equation of any normal to x2a2 - y2b2 = 1 is

                          axcosϕ + bycotϕ = a2 + b2 axcosϕ + bycotϕ - a2 + b2 = 0               ...(i)

The straight line lx + my - n = 0 will be normal to the hyperbolax2a2 - y2b2 = 1, then Eq. (i) and lx + my - n = 0 represent the same line.

 acosϕl = bcotϕm = a2 + b2n    secϕ = nala2 + b2and    tanϕ = nbma2 + b2 sec2ϕ - tan2ϕ = 1 n2a2l2a2 + b22 - n2b2m2a2 + b22 = 1 a2l2 - b2m2 = a2 + b22n2But given equation of normal is       a2l2 - b2m2 = a2 + b22k                  k = n2


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10.

If cosα + isinα, b = cosβ + isinβ, c = cosγ + isinγ and bc + ca + ab = 1, then cosβ - γ + cosγ - α + cosα - β is equal to

  • 32

  • 32

  • 0

  • 1


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