The value of sin2sin-10.8 is equal to from Mathematics JEE

Subject

Mathematics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

If y = (tan-1(x)), then (x2 + 1)2y2 + 2x(x2 + 1)y1 is equal to

  • 4

  • 0

  • 2

  • 1


2.

If f(x) = x3 and g(x) = x3 - 4x in - 2  x , then consider the statements

(i) f(x) and g(x) satisfy mean value theorem.

(ii) f(x) and g(x) both satisfy Rolle's theorem.

(iii)  Only g(x) satisfies Rolle's theorem.

Of these statements.

  • (i) and (ii) are correct

  • only (i) is correct

  • None is correct

  • (i) and (iii) are correct


3.

The tangent to the curve y = x3 + 1 at (1, 2) makes an angle θ with y-axis, then the value of tanθ is

  • - 13

  • 3

  • - 3

  • 13


4.

If the function f(x) defined by fx = x100100 + x9999 + ... + x22 +x+1, then f'(0) is equal to

  • 100f'(0)

  • 100

  • 1

  • - 1


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5.

Let S be the set of all real numbers. A relation R has been defined on S by aRb  a - b  1, then R is

  • symmetric and transitive but not reflexive

  • reflexive and transitive but not symmetrIc

  • reflexive and symmetric but not transitive

  • an equivalence relation


6.

For any two real numbers, an operation * defined by a * b  = 1 + ab is

  • neither commutative nor associative

  • commutative but not associative

  • both commutative and associative

  • associative but not commutative


7.

Let f : N  N defined by f(n) = n +12, if n is oddn2,     if n is even, then f is

  • onto but not one-one

  • one-one and onto

  • neither one-one nor onto

  • one-one but not onto


8.

Suppose f(x) = (x + 1)for x  - 1. If g(x) is a function whose graph is the reflection of the graph of f(x) in the line y = x, then g(x) is equal to

  • 1x + 12x > - 1

  • - x - 1

  • x + 1

  • x - 1


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9.

Given 0  x  12, then the value of tansin-1x2 + 1 - x22 - sin-1x is

  • 1

  • 3

  • - 1

  • 13


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10.

The value of sin2sin-10.8 is equal to

  • 0.48

  • sin1.2°

  • sin1.6°

  • 0.96


D.

0.96

Let E = sin2sin-10.8Put sin-10.8 = θ          sinθ = 0.8 cosθ = 1 - sin2θ                = 1 - 0.64 = 0.36 = 0.6        E = sin2θ = 2sinθcosθ               = 2 × 0.8 × 0.6 = 0.96


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