Equation of line passing through the point (2, 3, 1) and parallel to the line of intersection of the planes x - 2y - z + 5 = 0 and x + y + 3z = 6 is
D.
Let the DR's of !me passmg through intersectron of the given two planes x - 2y - z + 5 = 0 and , x + y + 3z = 6 are a, b and c
Then, a + 2b - c = 0
and a + b + 3c = 0
Since, required line passes through (2, 3, 1) and parallel to above line Hence, its equation will be
Foot of perpendicular drawn from the origin to the plane 2x - 3y + 4z = 29 is
(7, - 1, 3)
(5, - 1, 4)
(5, - 2, 3)
(2, - 3, 4)
A man takes a step forward probability 0.4 and one step backward with probability 0.6, then the probability that at the end of eleven steps he is one step away from the starting point, is
The probability distribution of X is
X | 0 | 1 | 2 | 3 |
P(X) | 0.2 | k | k | 2k |
Find the value of k.
0.4
0.2
0.1
0.3