Let ∆ = Axx21Byy21Czz21 and ∆1 = ABCx2y2z2111, then AxByCzx2y2z2111
∆1 = 2∆
∆1 = - ∆
∆1 = ∆
∆1 ≠ ∆
The function f(x) = x2 + 2x - 5 is strictly increasing in the interval
(- ∞, - 1)
[- 1, ∞)
(- ∞, 1]
(- 1, ∞)
The point on the curve y2 = x where the tangent makes an angle of π/4 with X-axis is
(4, 2)
12, 14
14, 12
(1, 1)
C.
We have, y2 = x ...i∴ 2ydydx = 1⇒ dydx = 12y∴ Slope of tangent = 12y ...iiNow, tangent makes an angle of π/4 wth X-axis∴ Slope of tangent = tanπ4 = 1 ...iiiFrom Eqs (ii) and (iii), we get 12y = 1 ⇒ y = 12Putting, y =12 in Eq. (i), we get 122 = x⇒ x = 14∴ Required point is 14, 12.
If 3xx1 = 3241, then x is equal to
4
8
2
± 22
If 2130x + y012 = 5618, then the value of x and y are
x = 3, y = 3
x = - 3, y = 3
x = 3, y = - 3
x = - 3, y = - 3
The range of sec-1x is
0, π - π2
- π2, π2
0, π
If y = fxgxhxlmnabc, then dydx is equal to
f'xg'xh'xlmnabc
lmnfxgxhxabc
f'xlag'xmbh'xnc
lmnabcf'xg'xh'x
If A is a square matrix of order 3 x 3, then KA is equal to
k2A
KA
3KA
k3A
If A = 1πsin-1πxtan-1xπsin-1xπcot-1πx, B = - cos-1πxtan-1xπsin-1xπ- tan-1πx, then A - B is
0
12I
I
2I
If f(x) = kx2 if x ≤ 23 if x > 2is continuous at x = 2, then the value of k is
3/4
4/3
3