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JEE Physics Solved Question Paper 2007

Multiple Choice Questions

The work done in moving an alpha particle between two points having potential difference 25 V is

8 × 10^-18J
8 × 10^-19J
8 × 10^-20 J
8 × 10^-16 J

The physical quantity angular momentum has the same dimensions as that of

work
force
Planck's constant
torque

The values of two resistors are R₁ = (6 ± 0.3)kΩ and R₂ = (10 ± 0.2)kΩ. The percentage error in the equivalent resistance when they are connected in parallel is

5.125 %
2 %
10.125 %
7 %

Two trains are moving with equal speed in opposite directions along two parallel railway tracks. If the wind is blowing with speed u along the track so that the relative velocities of the trains with respect to the wind are in the ratio 1 : 2, then the speed of each train must be

Two balls are dropped to the ground from different heights. One ball is dropped 2 s after the other but they both strike the ground at the same time. If the first ball takes 5 s to reach the ground, then the difference in initial heights is (g = 10 ms^-2)

20 m
80 m
170 m
40 m

A ball is thrown vertically upwards with a velocity of 25 ms^-1 from the top of a tower of height 30 m. How long will it travel before it hits ground ?

6 s
5 s
4 s
12 s

7.
A ball is projected from the ground at a speed of 10 ms^-1 making an angle of 30° with the horizontal. Another ball is simultaneously released from a point on the vertical line along the maximum height of the projectile. The initial height of the second ball is (g = 10 ms^-2)

6.25 m

2.5 m

1.25 m

5 m

2.5 m

Maximum height of projectile

$h = \frac{u^{2} \sin^{2} θ}{2 g} ∴ h = \frac{{(10)}^{2} \times \sin^{2} (30 °)}{2 \times 10} = \frac{5}{4} = 1.25 m$

Time to reach maximum height

$t = \frac{u \sin θ}{g} ∴ t = \frac{10 \times \sin 30 °}{10} = 0.5 s$

So, distance of vertical fall in 0.5 s

$s = \frac{1}{2} {gt}^{2} or s = \frac{1}{2} \times 10 \times {(0.5)}^{2} = 1.25 m$

∴ Height of second ball = 1.25 + 1.25 = 2.5 m

The sum of the magnitudes of two forces acting at a point is 18 N and the magnitude of their resultant is 12 N. If the resultant is at 90° with the smaller force, the magnitude of the forces in N are

6, 12
11, 7
5, 13
14, 4

The position of a particle is given by $r = \hat{i} + 2 \hat{j} - \hat{k}$ and its linear momentum is given by $p = 3 \hat{i} + 4 \hat{j} - 2 \hat{k}$ . Then its angular momentum, about the origin is perpendicular to

yz-plane
z-axis
y-axis
x-axis

10.

A mass of 6 kg is suspended by a rope of length 2 m from a ceiling. A force of 50 N in the horizontal direction is applied at the mid-point of the rope. The angle made by the rope with the vertical, in equilibrium is