Subject

Physics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

41.

Identify the correctly matched pair

  • Diamagnetic   —   Gadolinium

  • Soft ferromagnetic   —   Alnico

  • Hard ferromagnetic   —   Copper

  • Paramagnetic   —   Sodium


42.

If the radius of the dees of cyclotron is r, then the kinetic energy of a proton of mass m accelerated by the cyclotron at an oscillating frequency v is

  • 4π2m2v2r2

  • 4π2mv2r2

  • 2π2mv2r2

  • π2mv2r2


43.

If a magnetic dipole of moment M situated in the direction of a magnetic field B is rotated by 180°, then the amount of work done is

  • MB

  • 2 MB

  • MB2

  • Zero


44.

The polarity of induced emf is given by

  • Ampere's circuital law

  • Biot-Savart's law

  • Lenz's law

  • Fleming's right hand rule


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45.

In an L-C-R series circuit, at resonance

  • the current and voltage are in phase

  • the impedance is maximum

  • the current is minimum

  • the quality factor is independent of R


46.

A conducting ring of radius 1 m kept in a uniform magnetic field B of 0.01 T, rotates uniformly with an angular velocity 100 rads-1 with its axis of rotation perpendicular to B. The maximum induced emf in it is

  • 1.5 π V

  • π V

  • 2π V

  • 0.5 π V


47.

A step-down transformer increases the input current 4 A to 24 A at the secondary. If the number of turns in the primary coil is 330, the number of turns in the secondary coil is

  • 60

  • 50

  • 55

  • 45


48.

In a plane electromagnetic wave, the electric field of amplitude 1 Vm-1 varies with time in free space. The average energy density of magnetic field is (in Jm-2)

  • 8.86 × 10-12

  • 4.43 × 10-12

  • 17.72 × 10-12

  • 2.21 × 10-12


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49.

Which one of the following is the property of a monochromatic, plane electromagnetic wave in free space?

  • Electric and magnetic fields have a phase difference of π2

  • The energy contribution of both electric and magnetic fields are equal.

  • The direction of propagation is in the direction of electric field E

  • The pressure exerted by the wave is the product of energy density and the speed of the wave


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50.

A plane square sheet of charge of side 0.5 m has uniform surface charge density. An electron at 1 cm from the centre of the sheet experiences a force of 1.6 x 10-12 N directed away from the sheet. The total charge on the plane square sheet is (ε0 = 8.854 × 10-12 C2 m-2 N-1)

  • 16.25 µC

  • − 22.15 µC

  • − 44.27 µC

  • 144.27 µC


C.

− 44.27 µC

Given, l = 0.5 m

              

 F = 1.6 × 10-12 N

 q = − 1.6 × 10-19 C  (for electron)

ε0 = 8.854 × 10-12 C2 m-2 N-1

Electric field E = Fqor                 F = qE                      ........ (i)

Electric field due to a square plane sheet of charge

                E = σ2ε0

where, σ = surface charge density

          ε0 =  permittivity of free space

Putting the value of E in Eq. (i), we get

          F = q . σ2ε0 σ =2ε0 . Fq σ = 2 × 8.854 × 10-12 × 1.6 × 10-12- 1.6 × 10-19  σ = - 17.708 × 10-5σA = l2 × (-17.708 × 10-5)      = 0.5 × 0.5 × - 17.708 × 10-5      = - 4.427 × 10-5      = - 44.27 × 10-6 C      = - 44.27 μC


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