The following observations were taken for determining surface te

Subject

Physics

Class

JEE Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

The moment of inertia of a uniform cylinder of length

  • 1

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2.

A body of mass m = 10–2 kg is moving in a medium and experiences a frictional force F = –kv2. Its initial speed is v0 = 10 ms–1. If, after 10 s, its energy is 1/8 mv02,the value of k will be

  • 10-4 kg m-1

  • 10–1 kg m–1 s–1

  • 10-3 kg m-1

  • 10-3 kg m-1

829 Views

3.

A slender uniform rod of mass M and length

  • fraction numerator 3 straight g over denominator 2 calligraphic l end fraction space cos space straight theta
  • fraction numerator 2 space straight g over denominator 3 space calligraphic l end fraction space cos space straight theta
  • fraction numerator 3 straight g over denominator 2 space calligraphic l end fraction space sin space straight theta
  • fraction numerator 3 straight g over denominator 2 space calligraphic l end fraction space sin space straight theta
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4.

The variation of acceleration due to gravity g with distance d from centre of the earth is best represented by (R = Earth's radius)

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5.

A particle A of mass m and initial velocity v collides with a particle B of mass m/2 which is at rest. The collision is head on, and elastic. The ratio of the de-Broglie wavelengths λA to λB after the collision is

  • straight lambda subscript straight A over straight lambda subscript straight B space equals space 2 over 3
  • straight lambda subscript straight A over straight lambda subscript straight B space equals space 1 half
  • straight lambda subscript straight A over straight lambda subscript straight B space equals space 1 third
  • straight lambda subscript straight A over straight lambda subscript straight B space equals space 1 third
1144 Views

6.

A time-dependent force F = 6t acts on a particle of mass 1 kg. If the particle starts from rest, the work done by the force during the first 1 sec. will be

  • 9J

  • 18 J

  • 4.5 J

  • 4.5 J

1105 Views

7.

A body is thrown vertically upwards. Which one of the following graphs correctly represent the velocity vs time?

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8.

A particle is executing simple harmonic motion with a time period T. AT time t = 0, it is at its position of equilibrium. The kinetic energy-time graph of the particle will look like 

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9.

The temperature of an open room of volume 30 m3 increases from 17°C to 27°C due to sunshine. The atmospheric pressure in the room remains 1 × 105 Pa. If ni and nf are the numbers of molecules in the room before and after heating, then nf – ni will be

  • 2.5 x 1025

  • -2.5 x 1025

  • -1.61 x 1023

  • -1.61 x 1023

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10.

The following observations were taken for determining surface tension T of water by the capillary method :
Diameter of capillary, D = 1.25 × 10–2 m rise of water, h = 1.45 × 10–2 m
Using g = 9.80 m/s2 and the simplified relation T = (rhg/2) x103 n/m, the possible error in surface tension is closest to:

  • 2.4%

  • 10%

  • 0.15%

  • 0.15%


D.

0.15%

straight T space equals space rhg over 2 space straight x space 10 cubed
fraction numerator increment straight T over denominator straight T end fraction space equals space fraction numerator increment straight r over denominator straight r end fraction space plus space fraction numerator increment straight h over denominator straight h end fraction space plus 0
100 space straight x space fraction numerator increment straight T over denominator straight T end fraction space equals space open parentheses fraction numerator 10 to the power of negative 2 end exponent space straight x space.01 over denominator 1.25 space straight x space 10 to the power of negative 2 end exponent end fraction space plus fraction numerator 10 to the power of negative 2 end exponent space straight x space 0.1 over denominator 1.45 space straight x space 10 to the power of negative 2 end exponent end fraction close parentheses 100
space equals space 0.8 space plus 0.689
equals space 1.489
space 100 space straight x space fraction numerator increment straight T over denominator straight T end fraction space equals space 1.489 percent sign
space approximately equal to space 1.5 space percent sign
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