The solubility of in water is Sb2S3 in water is 1.0 x 10-5 mol/litre at 298 K .What will be its solubility product ?
108 x 10-25
1.0 x 10-25
144 x 10-25
126 x 10-25
What will be the pH value of 0.05 M Ba(OH)2 solution ?
12
13
1
12.96
B.
13
0.05 M Ba(OH)2 Solution
= 2 x 0.05 N Ba(OH)2
= 0.10 N Ba(OH)2
pOH = -log [OH-]
= - log (0.10) = 1
pH = 14 - pOH
= 14 - 1 = 13
Which of the following salt does not get hydrolysed in water ?
KClO4
NH4Cl
CH3COONa
None of these
In the reaction :
H2 + I2 2HI
In a 2 litre flask 0.4 moles of each H2 and I2 are taken .At equilibrium 0.5 moles of HI are formed .What will be the value of equilibrium constant ,Kc ?
20.2
25.4
0.284
11.11
KI and CuSO4 solution when mixed , give :
CuI2 + K2SO4
Cu2I2 + K2SO4
K2SO4 + Cu2I2 + I2
K2SO4 + CuI2 + I2