The volume of 10N and 4N HCl required to make 1 L of 7N HCl are :

Subject

Chemistry

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

2SO2 (g) + O2 (g) V2O5 (s)  is an example for :

  • neutralisation reaction

  • homogeneous catalysis

  • heterogeneous catalysis

  • irreversible reaction


2.

During the formation of a chemical bond :

  • electron-electron repulsion becomes more than the nucleus-electron attraction

  • energy of the system does not change

  • energy increases

  • energy decreases


3.

Which ofthe following is an intensive property ?

  • Temperature

  • Viscosity

  • Surface tension

  • All of these


4.

In equilibrium state , the value of G is :

  • zero

  • negative

  • positive

  • may be negative or positive


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5.

Molarity of a given orthophosphoric acid solution is 3 M .It's normality is :

  • 9 N

  • 0.3 N

  • 3 N

  • 1 N


6.

Hydroxyl ion concentration of 10-2 M HCl is :

  • 1 x 101 mol dm-3

  • 1 x 10-12 mol dm-3

  • 1 x 10-1 mol dm-3

  • 1 x 10-14 mol dm-3


7.

For a certain particle , it is found that uncertainty in velocity is reciprocal of uncertainty in position .This implies that :

  • mass of particle > unity

  • mass of particle = unity

  • mass of particle  h

  • mass of particle  h / 4π


8.

Entropy of the universe is :

  • constant

  • zero

  • continuously decreasing

  • continuously increasing


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9.

Which one of the following salts on being dissolved in water gives pH > 7 at 25°C ?

  • KCN

  • KNO3

  • NH4Cl

  • NH4CN


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10.

The volume of 10N and 4N HCl required to make 1 L of 7N HCl are :

  • 0.50 L of 10N HCl and 0.50 L of 4N HCl

  • 0.60 L of 10N HCl and 0.40 L of 4N HCl

  • 0.80 L of 10N HCl and 0.20 L of 4N HCl

  • 0.75 L of 10N HCl and 0.25 L of 4N HCl


A.

0.50 L of 10N HCl and 0.50 L of 4N HCl

Let V litre of 10 N HCl be mixed with (1 - V) litre of 4N HCl to give (V + 1 - V) = 1 L of 7N HCl .

N1V1 + N2V2 = N V

10V + 4 (1 - V) = 7 x 1

10 V + 4 - 4 V = 7

6 V = 7 - 4

V = 36 = 0.50 L

Volume of 10 N HCl = 0.50 L

Volume of 4 N HCl = 1 - 0.50 = 0.50 L


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